jee main chemistry important questions | Organic Compounds Containing Nitrogen jee main questions FREE

Q 1 :

Given below are two statements:

Statement (I): The ${NH}_{2}$ group in Aniline is ortho and para directing and a powerful activating group.

Statement (II): Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).

In the light of the above statements, choose the most appropriate answer from the options given below: [2024]

Both Statement I and Statement II are correct
Both Statement I and Statement II are incorrect
Statement I is incorrect but Statement II is correct
Statement I is correct but Statement II is incorrect

1

2

3

4

(1)

Statement (I): Due to its +M effect, $- {NH}_{2}$ group increases electron density at ortho and para positions of the benzene ring and hence it is ortho and para directing for electrophilic aromatic substitution reactions.

Statement (II): Aniline forms salt with aluminium chloride, a Lewis acid, used as a catalyst in Friedel-Crafts reaction. Due to this, nitrogen of aniline acquires positive charge and hence acts as a strong deactivating group for further reaction. Hence, Aniline does not undergo Friedel-Crafts reaction (alkylation and acetylation).

Q 2 :

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ $\times 10^{- 1}$ g. [2024]

(95)

Number of moles of aniline $(n_{C_{6} H_{5} {NH}_{2}}) = \frac{Given mass}{Molar mass} = \frac{6.55}{93} mol$

Maximum 0.07 mol of acetanilide can be obtained from 0.07 mol of aniline.

Maximum amount of acetanilide = number of moles × molar

mass of acetanilide = $\frac{6.55}{93} \times 135 g = 9.5 g = 95 \times 10^{- 1} g$

Q 3 :

The product A formed in the following reaction is [2024]

1

2

3

4

(4)

Q 4 :

Identify the product (A) in the following reaction. [2024]

1

2

3

4

(4)

Q 5 :

9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ‘P’. The mass of product ‘P’ obtained is 26.4 g. The percentage yield is ______ %. [2024]

(80)

$n_{C_{6} H_{5} N H_{2}} = \frac{W_{C_{6} H_{5} N H_{2}}}{M_{C_{6} H_{5} N H_{2}}} = \frac{9.3 g}{93 {gmol}^{- 1}} = 0.1 mol$

$n_{C_{6} H_{3} B r_{3} N H_{2}} = \frac{W_{C_{6} H_{3} B r_{3} N H_{2}}}{M_{C_{6} H_{3} B r_{3} N H_{2}}} = \frac{26.4 g}{330 {gmol}^{- 1}} = 0.08 mol$

If the reaction was 100% complete, the moles of $C_{6} H_{3} {Br}_{3} {NH}_{2}$ would be 0.1 mol.

$Percentage yield of reaction = \frac{Amount of product formed}{Amount of product expected for 100% yield} \times 100$

$= \frac{0.08}{0.1} \times 100 = 80 %$

Q 6 :

9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _______ g. (nearest integer) [2024]

(20)

$n_{aniline} = \frac{Given mass}{Molar mass} = \frac{9.3 g}{93 g m o l^{- 1}} = 0.1 m o l$

$n_{dye} = n_{aniline} = 0.1 m o l$

$W_{dye} = n_{dye} \times M_{dye} = 0.1 m o l \times 198 g m o l^{- 1} = 19.8 g \approx 20 g$

Q 7 :

If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ______ g. (nearest integer)
(consider complete conversion) [2024]

(591)

Number of moles of aniline $(n_{C_{6} H_{5} {NH}_{2}})$

$= \frac{Given mass}{Molar mass} = \frac{279 g}{93 {g mol}^{- 1}} = 3 mol$

$C_{6} H_{5} N_{2} C_{6} H_{4} {NH}_{2}$

$M = (12 \times 12) + (3 \times 14) + (14 \times 1) + (11 \times 1) = 197$

Moles of yellow dye = moles of aniline = 3 mol

Mass of yellow dye = number of moles × molar mass

$= 3 mol \times 197 {g mol}^{- 1} = 591 g$

Q 8 :

For reaction

The correct order of set of reagents for the above conversion is: [2025]

${Br}_{2} | {FeBr}_{3}, H_{2} O (Δ), NaOH$
$H_{2} {SO}_{4}, {Ac}_{2} O, {Br}_{2}, H_{2} O (Δ), NaOH$
${Ac}_{2} O, {Br}_{2}, H_{2} O (Δ), NaOH$
${Ac}_{2} O, H_{2} {SO}_{4}, {Br}_{2}, NaOH$

1

2

3

4

(2)

Q 9 :

The sequence from the following that would result in giving predominantly 3, 4, 5-tribromoaniline is: [2025]

1

2

3

4

(3)

Q 10 :

Consider the following sequence of reactions:

11.25 mg of chlorobenzene will produce ---- $\times 10^{- 1}$ mg of product B.

(Consider the reactions result in complete conversion.)

[Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g ${mol}^{- 1}$ respectively] [2025]

(93)

Moles of chlorobenzene $(n_{C_{6} H_{5} Cl})$ = $\frac{W_{C_{6} H_{5} Cl}}{M_{C_{6} H_{5} Cl}}$

$= \frac{11.25 \times 10^{- 3}}{112.5} mol = 10^{- 4} mol$

Moles of B = $n_{C_{6} H_{5} Cl} = 10^{- 4}$ mol

$Mass of B = moles of B \times molar mass of B = 10^{- 4} \times 93 g$

$= 93 \times 10^{- 1} mg$

Q 11 :

Given below are two statements:

Statement I: Pure aniline and other arylamines are usually colourless.

Statement II: Arylamines get coloured on storage due to atmospheric reduction.

In the light of the above statements, choose the most appropriate answer from the options given below: [2023]

Both Statements I and Statements II are correct
Statements I is incorrect but Statements II is correct
Both Statements I and Statements II are incorrect
Statements I is correct but Statements II is incorrect

1

2

3

4

(4)

Arylamines get coloured due to atmospheric oxidation.

Q 12 :

Compound A from the following reaction sequence is: [2023]

Salicylic acid
Phenol
Benzoic acid
Aniline

1

2

3

4

(4)

Q 13 :

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with ${Br}_{2}$ and KOH forms compound (R) having molecular formula $C_{6} H_{7} N .$ Names of P, Q and R respectively are. [2026]

Benzoic acid, benzamide, aniline
Phenylethanoic acid, phenylethanamide, benzamine
Toluic acid, methylbenzamide, 2-methylaniline
Benzoic acid, 4-methylbenzamide, 4-methylaniline

1

2

3

4

(1)

Q 14 :

Consider the following reaction sequence

The percentage of nitrogen in product ‘T’ formed is ______ %. (Nearest integer)
(Given molar mass in g ${mol}^{- 1}$ : H : 1, C : 12, N : 14, O : 16) [2026]

(20)

$Mol. wt = 6 \times 12 + (6 \times 1) + (2 \times 14) + (2 \times 16)$ $= 138$

$% N = \frac{28}{138} \times 100 = 20.29 %$

Q 15 :

The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is ________ g (nearest integer).

(Given molar mass in g ${mol}^{- 1}$ H : 1, C : 12, N : 14, O : 16) [2026]

(10)

Q 16 :

Identify X in the sequence given:

1

2

3

4

(1)

Q 17 :

Which of the following process will produce 2° amine?

Gabriel synthesis
Hoffmann bromamide reaction
Reduction of carbylamines
Reduction of nitro compounds

1

2

3

4

(3)

Reduction of RNC will produce $R - NH - {CH}_{3}$ .

Q 18 :

Given below are two statements:

Statement I: Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine.

Statement II: Nitration of aniline with ${HNO}_{3} / H_{2} {SO}_{4}$ at 288 K produces $m$ -nitroaniline in higher amount than $o$ -nitroaniline (pH adjusted).

In the light of the above statements, choose the correct answer from the options given below: [2026]

Both Statement I and Statement II are true
Both Statement I and Statement II are false
Statement I is true but Statement II is false
Statement I is false but Statement II is true

1

2

3

4

(4)

Statement I:

Statement II:

Q 19 :

Identify the incorrect statements.

Choose the correct answer from the options given below: [2026]

A and D only
A and C only
B and C only
A and B only

1

2

3

4

(3)

(A) In aniline ( $Ph - {NH}_{2}$ ), lone pair on N is delocalized due to resonance. In benzyl amine ( ${PhCH}_{2} {NH}_{2}$ ), lone pair on N is localized. Thus ${PhCH}_{2} {NH}_{2}$ is a stronger base than $Ph - {NH}_{2}$ .

(B) Aromatic amines cannot be synthesised by Gabriel phthalimide synthesis.

Q 20 :

Product C of the following reaction sequence will be [2026]

1-Bromo-4-nitrobenzene
1,3,5-Tribromo-2-nitrobenzene
4-Bromo-1-nitrobenzene
1,3,5-Tribromobenzene

1

2

3

4

(2)

Q 21 :

Consider the following reactions sequence

When the product (P) is subjected to Carius analysis using ${AgNO}_{3}$ , 1.0 g of the product (P) will produce _____ g of the precipitate of AgBr. (Nearest Integer).

(Given: molar mass in g ${mol}^{- 1}$ C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108) [2026]

(1)

$M = 7 \times 12 + 8 \times 1 + 1 \times 14 + 1 \times 80 = 186$

$Moles of AgBr = Moles of Br = Moles of product P$

$= \frac{Mass of P}{Molar mass of P} = \frac{1}{186} mol$

$Mass of AgBr precipitated$

$= moles of AgBr \times molar mass of AgBr$

$= \frac{1}{186} \times 188 g = 1 g$

Topic Question Set

Q 2 :

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ $\times 10^{- 1}$ g. [2024]

Q 3 :

The product A formed in the following reaction is [2024]

Q 4 :

Identify the product (A) in the following reaction. [2024]

Q 5 :

9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ‘P’. The mass of product ‘P’ obtained is 26.4 g. The percentage yield is ______ %. [2024]

Q 6 :

9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _______ g. (nearest integer) [2024]

Q 7 :

If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ______ g. (nearest integer)
(consider complete conversion) [2024]

Q 8 :

For reaction

The correct order of set of reagents for the above conversion is: [2025]

Q 9 :

The sequence from the following that would result in giving predominantly 3, 4, 5-tribromoaniline is: [2025]

Q 10 :

Consider the following sequence of reactions:

11.25 mg of chlorobenzene will produce ---- $\times 10^{- 1}$ mg of product B.

(Consider the reactions result in complete conversion.)

[Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g ${mol}^{- 1}$ respectively] [2025]

Q 12 :

Compound A from the following reaction sequence is: [2023]

Q 13 :

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with ${Br}_{2}$ and KOH forms compound (R) having molecular formula $C_{6} H_{7} N .$ Names of P, Q and R respectively are. [2026]

Q 14 :

Consider the following reaction sequence

The percentage of nitrogen in product ‘T’ formed is ______ %. (Nearest integer)
(Given molar mass in g ${mol}^{- 1}$ : H : 1, C : 12, N : 14, O : 16) [2026]

Q 15 :

The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is ________ g (nearest integer).

(Given molar mass in g ${mol}^{- 1}$ H : 1, C : 12, N : 14, O : 16) [2026]

Q 16 :

Identify X in the sequence given:

Q 17 :

Which of the following process will produce 2° amine?

Q 19 :

Identify the incorrect statements.

Choose the correct answer from the options given below: [2026]

Q 20 :

Product C of the following reaction sequence will be [2026]

Want Us to Email you About Special Offers & Updates?

Topic Question Set

Q 2 : From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ ×10-1 g. [2024]

Q 3 : The product A formed in the following reaction is [2024]

Q 4 : Identify the product (A) in the following reaction. [2024]

Q 5 : 9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ‘P’. The mass of product ‘P’ obtained is 26.4 g. The percentage yield is ______ %. [2024]

Q 6 : 9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _______ g. (nearest integer) [2024]

Q 7 : If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ______ g. (nearest integer) (consider complete conversion) [2024]

Q 8 : For reaction The correct order of set of reagents for the above conversion is: [2025]

Q 9 : The sequence from the following that would result in giving predominantly 3, 4, 5-tribromoaniline is: [2025]

Q 10 : Consider the following sequence of reactions: 11.25 mg of chlorobenzene will produce ---- ×10-1 mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol-1 respectively] [2025]

Q 11 : Given below are two statements: Statement I: Pure aniline and other arylamines are usually colourless. Statement II: Arylamines get coloured on storage due to atmospheric reduction. In the light of the above statements, choose the most appropriate answer from the options given below: [2023]

Q 12 : Compound A from the following reaction sequence is: [2023]

Q 13 : An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with Br2 and KOH forms compound (R) having molecular formula C6H7N. Names of P, Q and R respectively are. [2026]

Q 14 : Consider the following reaction sequence The percentage of nitrogen in product ‘T’ formed is ______ %. (Nearest integer) (Given molar mass in g mol-1: H : 1, C : 12, N : 14, O : 16) [2026]

Q 15 : The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is ________ g (nearest integer). (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16) [2026]

Q 16 : Identify X in the sequence given:

Q 17 : Which of the following process will produce 2° amine?

Q 19 : Identify the incorrect statements. Choose the correct answer from the options given below: [2026]

Q 20 : Product C of the following reaction sequence will be [2026]

Q 21 : Consider the following reactions sequence When the product (P) is subjected to Carius analysis using AgNO3, 1.0 g of the product (P) will produce _____ g of the precipitate of AgBr. (Nearest Integer). (Given: molar mass in g mol-1 C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108) [2026]

Want Us to Email you About Special Offers & Updates?

Q 2 :

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ $\times 10^{- 1}$ g. [2024]

Q 3 :

The product A formed in the following reaction is [2024]

Q 4 :

Identify the product (A) in the following reaction. [2024]

Q 5 :

9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ‘P’. The mass of product ‘P’ obtained is 26.4 g. The percentage yield is ______ %. [2024]

Q 6 :

9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _______ g. (nearest integer) [2024]

Q 7 :

If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ______ g. (nearest integer)
(consider complete conversion) [2024]

Q 8 :

For reaction

The correct order of set of reagents for the above conversion is: [2025]

Q 9 :

The sequence from the following that would result in giving predominantly 3, 4, 5-tribromoaniline is: [2025]

Q 10 :

Consider the following sequence of reactions:

11.25 mg of chlorobenzene will produce ---- $\times 10^{- 1}$ mg of product B.

(Consider the reactions result in complete conversion.)

[Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g ${mol}^{- 1}$ respectively] [2025]

Q 12 :

Compound A from the following reaction sequence is: [2023]

Q 13 :

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with ${Br}_{2}$ and KOH forms compound (R) having molecular formula $C_{6} H_{7} N .$ Names of P, Q and R respectively are. [2026]

Q 14 :

Consider the following reaction sequence

The percentage of nitrogen in product ‘T’ formed is ______ %. (Nearest integer)
(Given molar mass in g ${mol}^{- 1}$ : H : 1, C : 12, N : 14, O : 16) [2026]

Q 15 :

The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is ________ g (nearest integer).

(Given molar mass in g ${mol}^{- 1}$ H : 1, C : 12, N : 14, O : 16) [2026]

Q 16 :

Identify X in the sequence given:

Q 17 :

Which of the following process will produce 2° amine?

Q 19 :

Identify the incorrect statements.

Choose the correct answer from the options given below: [2026]

Q 20 :

Product C of the following reaction sequence will be [2026]