If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ______ g. (nearest integer) (consider complete conversion)

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Solution

Q.
If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ______ g. (nearest integer)
(consider complete conversion) [2024]

Ans.
(591)

Number of moles of aniline $(n_{C_{6} H_{5} {NH}_{2}})$

$= \frac{Given mass}{Molar mass} = \frac{279 g}{93 {g mol}^{- 1}} = 3 mol$

$C_{6} H_{5} N_{2} C_{6} H_{4} {NH}_{2}$

$M = (12 \times 12) + (3 \times 14) + (14 \times 1) + (11 \times 1) = 197$

Moles of yellow dye = moles of aniline = 3 mol

Mass of yellow dye = number of moles × molar mass

$= 3 mol \times 197 {g mol}^{- 1} = 591 g$

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