Consider the following sequence of reactions: 11.25 mg of chlorobenzene will produce ---- mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g respectively]

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Solution

Q.
Consider the following sequence of reactions:

11.25 mg of chlorobenzene will produce ---- $\times 10^{- 1}$ mg of product B.

(Consider the reactions result in complete conversion.)

[Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g ${mol}^{- 1}$ respectively] [2025]

Ans.
(93)

Moles of chlorobenzene $(n_{C_{6} H_{5} Cl})$ = $\frac{W_{C_{6} H_{5} Cl}}{M_{C_{6} H_{5} Cl}}$

$= \frac{11.25 \times 10^{- 3}}{112.5} mol = 10^{- 4} mol$

Moles of B = $n_{C_{6} H_{5} Cl} = 10^{- 4}$ mol

$Mass of B = moles of B \times molar mass of B = 10^{- 4} \times 93 g$

$= 93 \times 10^{- 1} mg$

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