Q 21 :

The moment of inertia of a semicircular ring about an axis passing through the center and perpendicular to the plane of the ring is 1xMR2, where R is the radius and M is the mass of the semicircular ring. The value of x will be _______ .         [2023]



(1)

The moment of inertia of a semicircular ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is =MR2

So x=1



Q 22 :

A solid sphere and a solid cylinder of the same mass and radius are rolling on a horizontal surface without slipping. The ratio of their radius of gyration respectively (ksph:kcyl) is 2:x, then the value of x is _________ .             [2023]



(5)

For solid sphere, 25mR2=mksph2

ksph=25R

For solid cylinder, mR22=mkcyl2

kcyl=R2

ksphkcyl=2512=25=2x

 x=5



Q 23 :

The moment of inertia of a square loop made of four uniform solid cylinders, each having radius R and length L (R<L) about an axis passing through the mid points of opposite sides, is ______. (Take the mass of the entire loop as M).             [2026]

  • 38MR2+16ML2

     

  • 38MR2+712ML2

     

  • 34MR2+712ML2

     

  • 34MR2+16ML2

     

(1)

Inet=2(I1+I2)

=2(M'R24+M'212)+2(M'R22+M'(2)2)

=M'R22+M'R26+M'R2+M'22

=3M'R22+2M'23

Given masses M'=M4

So, I=3(M/4)R22+2(M/4)23

I=38MR2+M26



Q 24 :

Two identical thin rods of mass M kg and length L m are connected as shown in figure. Moment of inertia of the combined rod system about an axis passing through point P and perpendicular to the plane of the rods is x12ML2 kg m2. The value of x is __________.  [2026]



(17)

I=ML23+(ML212+ML2)

=4ML2+ML2+12ML212

I=1712ML2

  x=17



Q 25 :

A solid sphere of mass 5 kg and radius 10 cm is kept in contact with another solid sphere of mass 10 kg and radius 20 cm. The moment of inertia of this pair of spheres about the tangent passing through the point of contact is __________ kg·m2.            [2026]

  • 0.18

     

  • 0.63

     

  • 0.36

     

  • 0.72

     

(2)

I=75[m1R12+m2R22]

=75[5(10)2+10(20)2]×10-4

I=63×10-2 kg m2

I=0.63 kg m2



Q 26 :

A circular disc has radius R1 and thickness T1. Another circular disc made of the same material has radius R2 and thickness T2. If the moment of inertia of both discs are same and R1R2=2, then T1T2=1α. The value of α is _______.           [2026]



(16)

m1=πR12T1ρ    m2=πR22T2ρ

I1=m1R122    I2=m2R222

I1=I2

πR12T1ρR122=πR22T2ρR222T1T2=116



Q 27 :

A uniform solid cylinder of length L and radius R has moment of inertia about its axis equal to I1. A small co-centric cylinder of length L2 and radius R3 carved from this cylinder has moment of inertia about its axis equals to I2. The ratio I1/I2 is _________.             [2026]



(162)

Original mass (M)

The removed mass (m)

m=ρ×π(R3)2×L2

=ρ.πR2L18=M18

I'=12·M18·R29=1324MR2

II'=12MR21324MR2=162



Q 28 :

Suppose there is a uniform circular disc of mass M kg and radius r m shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis A of the disc is given by x256Mr2 The value of x is ______.   [2026]



(109)

M=σπR2

σπR2=16m

m=σπR216

Isystem=MR22-2(mR22×16+9mR216)

=MR22-2×19mR232

=MR22-1916mR2

=MR22-19256MR2  because m=M16

=(128-19)MR2256

=109MR2256



Q 29 :

A solid sphere of radius 10 cm is rotating about an axis which is at a distance 15 cm from its centre. The radius of gyration about this axis is n cm. The value of n is _____. [2026]



(265)

Let radius of gyration is k

mk2=23mR2+md2

k2=23×102+152=265

(n)2=265n=265