Q 1 :

Given below are two statements :

Statement I: The number of pairs among [SiO2, CO2], [SnO, SnO2], [PbO, PbO2] and [GeO, GeO2] which contain oxides that are both amphoteric is 2.

Statement II: BF3 is an electron deficient molecule, can act as a Lewis acid, forms adduct with NH3 and has a trigonal planar geometry.

In the light of the above statements, choose the correct answer from the options given below             [2026]

  • Statement I is false but Statement II is true

     

  • Both Statement I and Statement II are false

     

  • Statement I is true but Statement II is false

     

  • Both Statement I and Statement II are true

     

(4)

⇒SiO2, CO2, GeO, GeO2 are acidic in nature.

SnO, SnO2, PbO, PbO2 are amphoteric in nature.

⇒BF3 is Lewis acid according to Lewis octet theory and has sp2 hybridization with trigonal planar geometry and it can accept lone pair from ammonia to form adduct.



Q 2 :

Choose the INCORRECT statement             [2026]

  • Among the isotopes of carbon, C13 is a radioactive isotope.

     

  • Carbon cannot exceed its covalency more than four.

     

  • CO2 is the most acidic oxide among the dioxides of group 14 elements.

     

  • Carbon exhibits negative oxidation states along with +4 and +2.

     

(1)

C13 is not radioactive

C14 is radioactive



Q 3 :

It is noticed that Pb2+ is more stable than Pb4+ but Sn2+ is less stable than Sn4+. 

Observe the following reactions.

PbO2+Pb→2PbO; ΔrG°(1)

SnO2+Sn→2SnO; ΔrG°(2)

Identify the correct set from the following:  [2026]

  • ΔrG°(1)<0 ; ΔrG°(2)<0

     

  • ΔrG°(1)<0 ; ΔrG°(2)>0

     

  • ΔrG°(1)>0 ; ΔrG°(2)>0

     

  • ΔrG°(1)>0 ; ΔrG°(2)<0

     

(2)

PbO2+Pb→2PbO

Pb2+ is more stable hence reaction will be spontaneous. So ΔGr°(1) is negative.

SnO2+Sn→2SnO

Sn2+ is less stable, so reaction will be non-spontaneous hence ΔGr°(2) is positive.



Q 4 :

Which of the following statements is incorrect?

  • In [SiF6]2-, [GeCl6]2- and [Sn(OH)6]2-; the central atoms are in sp3d2 hybridized state.

     

  • Both Carbon and Silicon cannot exceed their covalence more than four.

     

  • Lead is more stable in +2 oxidation state due to inert pair effect.

     

  • In group-14 carbon has unique ability of forming pπ–pπ multiple bonds with itself and also with small sized atom like O, N etc.

     

(2)

C = 4, Si = 6



Q 5 :

Given below are two statements:

Statement I: The second ionization enthalpy of B, Al and Ga is in the order of B>Al>Ga.

Statement II: The correct order in terms of first ionisation enthalpy is Si<Ge<Pb<Sn.

In the light of the above statements, choose the correct answer from the options given below:         [2026]

  • Both Statement I and Statement II are true

     

  • Both Statement I and Statement II are false

     

  • Statement I is true but Statement II is false

     

  • Statement I is false but Statement II is true

     

(2)

Statement I: Trend of second ionization energy for group 13 elements is (data in kJ/mol):

B(2427)>Ga(1979)>Tl(1971)>In(1820)>Al(1816)

Statement II : Ionization energy decreases down the group. For group 14 elements, an exception is ionization of Pb is more than that of Sn due to poor shielding of 4f electrons. Thus, decreasing order of ionization energy for group 14 elements is (data in kJ/mol):

C (1086)>Si (786)>Ge (761)>Pb (715)>Sn (708)