Consider the following reactions
Na2B4O7→Δ2X+Y
CuSO4+Y→Non-luminous flameZ+SO3
2Z+2X+Carbon→Luminous flame2Q+Na2B4O7+CO
The oxidation states of Cu in Z and Q, respectively are: [2026]
+2 and +2
+1 and +1
+2 and +1
+1 and +2
(3)