Q 1 :

Consider the following reactions

Na2B4O7Δ2X+Y

CuSO4+YNon-luminous flameZ+SO3

2Z+2X+CarbonLuminous flame2Q+Na2B4O7+CO

The oxidation states of Cu in Z and Q, respectively are:  [2026]

  • +2 and +2

     

  • +1 and +1

     

  • +2 and +1

     

  • +1 and +2

     

(3)

Na2B4O7Δ(2NaBO2)(X)+B2O3

CuSO4+B2O3Non-luminous flameΔCu+2(BO2)2(Blue bead)(Z)+SO3

2Cu(BO2)2+2NaBO2+CLuminous flameΔ2Cu+1BO2Colorless(Q)+Na2B4O7+CO