Q 1 :

Two p-block elements X and Y form fluorides of the type EF3. The fluoride compound XF3 is a Lewis acid and YF3 is a Lewis base. The hybridizations of the central atoms of XF3 and YF3 respectively are             [2026]

  • Both sp2

     

  • Both sp3

     

  • sp2 and sp3

     

  • sp3 and sp2

     

(3)

XF3=BF3 ; sp2

YF3=NF3 ; sp3



Q 2 :

Given below are two statements:

Statement I: The increasing order of boiling point of hydrogen halides is HCl < HBr < HI < HF.

Statement II: The increasing order of melting point of hydrogen halides is HCl < HBr < HF < HI.

In the light of the above statements, choose the correct answer from the options given below:  [2026]

  • Both Statement I and Statement II are true

     

  • Statement I is false but Statement II is true

     

  • Statement I is true but Statement II is false

     

  • Both Statement I and Statement II are false

     

(1)

Correct order of

(i) Boiling point : HF>HI>HBr>HCl

(ii) Melting point : HI>HF>HBr>HCl



Q 3 :

Given below are two statements :

Statement I : Elements ‘X’ and ‘Y’ are the most and least electronegative elements, respectively among N, As, Sb and P. The nature of the oxides X2O3 and Y2O3 is acidic and amphoteric, respectively.

Statement II : BCl3 is covalent in nature and gets hydrolysed in water. It produces [B(OH)4]- and [B(H2O)6]3+ in aqueous medium.

In the light of the above statements, choose the correct answer from the options given below :      [2026]

  • Both Statement I and Statement II are true

     

  • Statement I is false but Statement II is true

     

  • Statement I is true but Statement II is false

     

  • Both Statement I and Statement II are false

     

(3)

Electronegativity order : N>P>As>Sb

                                                               ↑                 ↑

                               Most electronegative    Least electronegative

X=N       X2O3=N2O3 (Acidic)

Y=Sb    Y2O3=Sb2O3 (Amphoteric)

Statement-I is true

BCl3+3H2O→B(OH)3+3HCl

Statement-II is false



Q 4 :

A student added aqueous chlorine to aqueous sodium bromide and the resulting mixture was shaken with an equal volume of trichloroethane.

Which diagram best represents the observation made?

  •  

  •  

  •  

  •  

(4)

Cl2+2NaBr→Br2+2NaCl

Cl2 oxidises Br- to Br2 in trichloroethane and is reddish brown in colour. Two layers are observed as trichloroethane is immiscible with water.



Q 5 :

Match the Column – I and Column – II

  Column – I   Column – II
A) Hypophosphoric acid P) All hydrogens are ionizable in water
B) Pyrophosphoric acid Q) Lewis acid
C) Boric acid R) Monobasic acid
D) Hypophosphorous acid S) sp3 hybridized central atom

 

  • A-PS; B-PS; C-QR; D-RS

     

  • A-QR; B-PS; C-PQ; D-RS

     

  • A-PS; B-QR; C-RS; D-S

     

  • A-QS; B-PR; C-PQ; D-P

     

(1)

 



Q 6 :

Which one of the following orders is not in accordance with the property stated against it?

  • F>Cl>Br>I : Electronegativity

     

  • F2>Cl2>Br2>I2 : Bond dissociation energy

     

  • F2>Cl2>Br2>I2 : Oxidizing power

     

  • HI>HBr>HCl>HF : Acidic strength

     

(2)

(b) Bond dissociation energy order

Cl2>Br2>F2>I2242.6192.8158.8151.1 kJ/mol

 



Q 7 :

Given below are two statements one is labelled as Assertion A and other is labelled as Reason R

Assertion A: Fluorine forms only one oxoacid HOF. Where as other halogens forms more

Reason R: Fluorine has smallest size among all halogen and is highly electronegative

In the light of above statements choose, The most appropriate answer from the options given below

  • A is correct but R is not correct

     

  • A is not correct but R is correct

     

  • Both A and R are correct and R is the correct explanation of A

     

  • Both A and R are correct and R is not the correct explanation of A

     

(3)

Fluorine forms only oxy acid HOF due to smaller size and highest electronegativity



Q 8 :

Which of the following order is correct?

  • EF2/2F-∘<ECl2/2Cl-∘<EBr2/2Br-∘<EI2/2I-∘=Evalues∘ (SRP values)

     

  • I>Br>Cl>F; Electron affinity

     

  • F->Cl->Br->I-; |Hydration enthalpy|

     

  • F2>Cl2>Br2>I2; Bond dissociation enthalpy

     

(3)

i)  F2 to I2; SRP values decreases

ii)  Cl>F>Br>I; electron affinity

iii)  Cl2>Br2>F2>I2; BDE



Q 9 :

Given below are two statements:

Statement I: Oxidising power of halogens decreases in the order F2>Cl2>Br2>I2, which is the basis of "Layer test".

Statement II: "Layer test" to identify Br2 and I2 in aqueous solution involves the oxidation of bromide or iodide into Br2 or I2 respectively with Cl2, which is a type of displacement redox reaction.

In the light of the above statements, choose the correct answer from the options given below:             [2026]

  • Both Statement I and Statement II are true

     

  • Both Statement I and Statement II are false

     

  • Statement I is true but Statement II is false

     

  • Statement I is false but Statement II is true

     

(1)

Add 1 mL of CHCl3 or CCl4 and chlorine water in excess to the salt solution in water or sodium carbonate extract neutralised with dil. HCl and shake the test tube vigorously. Presence of violet and orange colouration in the organic layer confirms the presence of iodide and bromide ions respectively.

2NaI+Cl2→2NaCl+I2 (violet)

2NaI+Br2→2NaBr+Br2 (orange)