Q 1 :    

A 2 A current carrying straight metal wire of resistance 1 Ω, resistivity 2×10-6Ωm, area of cross-section 10 mm2 and mass 500 g is suspended horizontally in mid-air by applying a uniform magnetic field B. The magnitude of B is ____ ×10-1T (given, g = 10 m/s²)                           [2024]



(5)            R=ρlAl=RAρ=1×10×10-62×10-6=5m

                ilB=mgB=mgil

                B=(0.5)(10)2×5=5×10-1T

 



Q 2 :    

A charge of 4.0 μC is moving with a velocity of 4.0×106ms-1 along the positive y-axis under a magnetic field B of strength (2k^) T. The force acting on the charge is xi^ N. The value of x is ____.                       [2024]



(32)            q=4μC,v=4×106j^m/s,    B=2k^T

                  F=q(v×B)=4×10-6(4×106j^×2k^)

                 F=4×10-6×8×106i^=32i^N

                 x=32

 



Q 3 :    

A rigid wire consists of a semicircular portion of radius R and two straight sections. The wire is partially immersed in a perpendicular magnetic field B=B0j^ as shown in the figure. The magnetic force on the wire if it has a current i is              [2024]

  • -2iBRj^

     

  • 2iBRj^

     

  • -iBRj^

     

  • iBRj^

     

(1)

Note: Direction of magnetic field is in +k^

Force on current carrying wire,

F=i×B

Here, =2R

F=-2iRBj^

 



Q 4 :    

The magnetic field existing in a region is given by B=0.2(1+2x)k^T. A square loop of edge 50 cm carrying 0.5 A current is placed in the x – y plane with its edges parallel to the x – y axes, as shown in the figure. The magnitude of the net magnetic force experienced by the loop is ______ mN.                 [2024]



(50)

F=i(×B)

F3 and F4 will cancel each other.

F1=-0.5×50100×{0.2(1+4)}i^

=-12×12×1i^=-14i^=-0.25i^

F2=0.5×50100×{0.2(1+5)}i^=12×12×{1.2}i^=0.3i^

Fnet=0.05i^(N)=50 (mN)i^



Q 5 :    

A square loop of edge length 2 m carrying a current of 2 A is placed with its edges parallel to the x-y axis. A magnetic field is passing through the x-y plane and expressed as B=B0(1+4x)k^,  where B0=5T.. The net magnetic force experienced by the loop is ______ N.              [2024]



(160)

B(x=0)=B0,  B(x=2)=9B0

Also, F=i×B

F1=iB0(j^×k^)=iB0(i^)=2×2×5(i^)=20N(i^)

F2=9iB0(-j^×k^)=9iB0(-i^)=2×2×45(-i^)=180N(-i^)

Fnet on AD and CB=0

Fnet=F2-F1=160N(-i^)

Fnet=160N



Q 6 :    

The horizontal component of Earth's magnetic field at a place is 3.5×10-5T. A very long straight conductor carrying a current of 2A in the direction from South-East to North-West is placed. The force per unit length experienced by the conductor is ______ ×10-6N/m.         [2024]



(35)

F=IBsinθ

F=IBsinθ=2×3.5×10-5×sin45°

=2×3.5×10-5×12

=3.5×10-5=35×10-6 N/m