The horizontal component of Earth's magnetic field at a place is . A very long straight conductor carrying a current of in the direction from South-East to North-West is placed. The force per unit length experienced by the conductor is

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Solution

Q.
The horizontal component of Earth's magnetic field at a place is $3.5 \times 10^{- 5} T$ . A very long straight conductor carrying a current of $\sqrt{2} A$ in the direction from South-East to North-West is placed. The force per unit length experienced by the conductor is ______ $\times 10^{- 6} N / m$ . [2024]

Ans.
(35)

$F = I ℓ B \sin θ$

$\frac{F}{ℓ} = I B \sin θ = \sqrt{2} \times 3.5 \times 10^{- 5} \times \sin 45 °$

$= \sqrt{2} \times 3.5 \times 10^{- 5} \times \frac{1}{\sqrt{2}}$

$= 3.5 \times 10^{- 5} = 35 \times 10^{- 6} N/m$

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