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Solution


Q.

A 4.0 cm long straight wire carrying a current of 8 A is placed perpendicular to an uniform magnetic field of strength 0.15 T. The magnetic force on the wire is ______ mN.          [2025]

Ans.

(48)

F=IlB

F=8×4100×0.15=48×10–3 N= 48 mN