Q 1 :    

The electrostatic force (F1) and magnetic force (F2) acting on a charge q moving with velocity v can be written             [2024]

  • F1=qB,F2=q(B×v)

     

  • F1=qE,F2=q(v×B)

     

  • F1=qv·E,F2=q(B·v)

     

  • F1=qE,F2=q(B×v)

     

(B)     The electrostatic force acting on a charge, F1=qE

          The magnetic force acting on a charge F2=q(v×B)

 



Q 2 :    

A proton and a deuteron (q=+e,m=2.0u) having same kinetic energies enter a region of uniform magnetic field B , moving perpendicular to B. The ratio of the radius rd of deuteron path to the radius rp of the proton path is:                      [2024]

  • 1:1

     

  • 1:2

     

  • 2:1

     

  • 1:2

     

(C)      As radius of circular path (r)=mvqB                               (i)

           Given (KE)p=(KE)d

            12mpvp2=12mdvd2mpvp2=mdvd2

            As md=2mpmpvp2=2mpvd2vp=2vd

           Now from equation (i),

           rprd=mpvpeB×eB2mpvd=12=rd:rp=2:1

 



Q 3 :    

A proton moving with a constant velocity passes through a region of space without any change in its velocity. If E¯ and B¯ represent the electric and magnetic fields respectively, then the region of space may have:

(A) E = 0, B = 0                                (B) E = 0, B ≠ 0

(C) E ≠ 0, B = 0                                (D) E ≠ 0, B ≠ 0

Choose the most appropriate answer from the options given below:                                   [2024]

  • (A), (B) and (C) only

     

  • (A), (C) and (D) only

     

  • (A), (B) and (D) only

     

  • (B), (C) and (D) only

     

(C)      Net force on particle must be zero i.e.

           qE+qV×B=0

           Possible cases are

           (i)  E and B=0

           (ii)  V×B=0,E=0

           (iii)  qE=-qV×B

            E0 and B0

 



Q 4 :    

Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describes circular paths of radii R1 and R2 respectively. The mass ratio of and Y is                    [2024]

  • (R1R2)

     

  • (R2R1)2

     

  • (R2R1)

     

  • (R1R2)2

     

(D)      R=mvqB=pqB=2m(KE)qB=2mqVqB

          RmmR2

          m1m2=(R1R2)2

 



Q 5 :    

An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3 μT perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that the electron moves along the same path, is ____ NC-1. (Given, mass of electron =9×10-31 kg, electric charge =1.6×10-19C)                         [2024]



(4)            For the given condition of moving undeflected, net force should be zero.

                qE=qVBE=VB

                E=2×KEm×B=2×5×1.6×10-199×10-31×3×10-6=4 N/C

 



Q 6 :    

An electron moves through a uniform magnetic field B=B0i^+2B0J^T. At a particular instant of time, the velocity of electron is u=3i^+5j^ m/s. If the magnetic force acting on electron is F=5ek^ N, where e is the charge of electron, then the value of B0 is ____ T.                    [2024]



(5)        F=q(v×B)

             5ek^=e(3i^+5j^)×(B0i^+2B0j^)

             5ek^=e(6B0k^-5B0k^)B0=5T