Constraint Relations questions | Constraint Relations jee questions

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Q 1 :

As per given figure, a weightless pulley P is attached on a double inclined frictionless surfaces. The tension in the string (massless) will be (if g = 10 $m / s^{2}$ ) [2023]

$(4 \sqrt{3} - 1) N$
$4 (\sqrt{3} - 1) N$
$(4 \sqrt{3} + 1) N$
$4 (\sqrt{3} + 1) N$

(4)

$4 g \sin 60 ° - T = 4 a$ ...(i)

$T - g \sin 30 ° = a$ ...(ii)

Solving (i) and (ii), we get

$20 \sqrt{3} - T = 4 T - 20$

$\Rightarrow T = 4 (\sqrt{3} + 1) N$

Q 2 :

A hanging mass M is connected to a four times bigger mass by using a string-pulley arrangement, as shown in the figure. The bigger mass is placed on a fixed horizontal ice-slab and being pulled by 2 Mg force. In this situation. Tension in the string is $\frac{x}{5}$ Mg for $x$ = __________. Neglect mass of the string and friction of the block (bigger mass) with ice slab. (Given g = acceleration due to gravity)

(6)

$For 4 m$

$2 M g - T = 4 M a$ $. . . (i)$

$For M$

$T - m g = M a$ $. . . (i i)$

$Adding (i) & (ii), we get$

$M g = 5 M a \Rightarrow a = \frac{g}{5}$

$So, T = M a + M g = \frac{M g}{5} + M g = \frac{6}{5} M g$

Topic Question Set

Q 1 :

As per given figure, a weightless pulley P is attached on a double inclined frictionless surfaces. The tension in the string (massless) will be (if g = 10 $m / s^{2}$ ) [2023]

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Topic Question Set

Q 1 : As per given figure, a weightless pulley P is attached on a double inclined frictionless surfaces. The tension in the string (massless) will be (if g = 10 m/s2) [2023]

Want Us to Email you About Special Offers & Updates?

Q 1 :

As per given figure, a weightless pulley P is attached on a double inclined frictionless surfaces. The tension in the string (massless) will be (if g = 10 $m / s^{2}$ ) [2023]