Q 1 :

As per given figure, a weightless pulley P is attached on a double inclined frictionless surfaces. The tension in the string (massless) will be (if g = 10 m/s2)    [2023]

  • (43-1)N

     

  • 4(3-1)N

     

  • (43+1)N

     

  • 4(3+1)N

     

(4)

4gsin60°-T=4a              ...(i)

T-gsin30°=a                    ...(ii)

Solving (i) and (ii), we get

203-T=4T-20

T=4(3+1)N