Q 1 :    

 A 1 kg mass is suspended from the ceiling by a rope of length 4 m. A horizontal force 'F' is applied at the midpoint of the rope so that the rope makes an angle of 45° with respect to the vertical axis as shown in the figure. The magnitude of F is:         [2024]

  • 102N

     

  • 1 N

     

  • 110×2N

     

  • 10 N

     

(4)

As the system is in equilibrium, therefore

T1cos45°=mg

T1sin45°=F

 tan45°=FmgF=mg=10 N