Q 41 :

A source supplies heat to a system at the rate of 1000 W. If the system performs work at a rate of 200 W, then the rate at which the internal energy of the system increases is       [2023]

  • 800 W

     

  • 1200 W

     

  • 600 W

     

  • 500 W

     

(1)

dQ=dU+dW

dUdt=dQdt-dWdt

dUdt=1000-200=800 W



Q 42 :

Given below are two statements:                                   [2023]

Statement I: If heat is added to a system, its temperature must increase.

Statement II: If positive work is done by a system in a thermodynamic process, its volume must increase.

In the light of the above statements, choose the correct answer from the options given below:

  • Both Statement I and Statement II are true

     

  • Statement I is false but Statement II is true

     

  • Both Statement I and Statement II are false

     

  • Statement I is true but Statement II is false

     

(2)

Statement I: ΔQ>0

According to the first law of thermodynamics,

ΔQ=ΔU+W

If ΔQ>0, ΔU<0 and W>0 is also possible.  

Hence ΔT<0, so temperature decreases.

Statement I is false

Statement II: W>0

 PdV>0

Therefore, volume of the system must increase during positive work done by the system.

Statement II is true



Q 43 :

Consider two containers A and B containing monoatomic gases at the same pressure (P), volume (V) and temperature (T). The gas in A is compressed isothermally to 18 of its original volume, while the gas in B is compressed adiabatically to 18 of its original volume. The ratio of final pressure of gas in B to that of gas in A is:      [2023]

  • 8

     

  • 81/2

     

  • 18

     

  • 4

     

(4)

Isothermal process, T=constant

PV=nRT=constant

P1V1=P2V2

PV=PA(V8)

PA=8P

Adiabatic process, PVγ=constant

γ for monoatomic gas is 53

P1V1γ=P2V2γ

PBP=(V1V2)γ=(VV/8)5/3

PB=32P

PBPA=32P8P=4



Q 44 :

A gas is compressed adiabatically, which one of the following statement is NOT true?                      [2023]

  • There is no heat supplied to the system

     

  • The temperature of the gas increases

     

  • The change in the internal energy is equal to the work done on the gas

     

  • There is no change in the internal energy

     

(4)

(1) ΔQ=0

(2) ΔQ=ΔU+ΔWΔU=-ΔW

Adiabatic compression (V)

ΔW=-ve  ΔU=+ve

ΔUT

ΔU0



Q 45 :

1 kg of water at 100°C is converted into steam at 100°C by boiling at atmospheric pressure. The volume of water changes from 1.00×10-3m3 as a liquid to 1.671 m3 as steam. The change in internal energy of the system during the process will be (Given latent heat of vaporisation =2257 kJ/kg, atmospheric pressure =1×105 Pa)         [2023]

  • + 2090 kJ

     

  • - 2090 kJ

     

  • - 2426 kJ

     

  • + 2476 kJ

     

(1)

ΔQ=ΔU+ΔW

  ΔU=ΔQ-ΔW=mLv-PΔV

                =(1 kg)(2257×103J/kg)

-(1×105 Pa)(1.671 m3-1×10-3 m3)

           =2257×103 J-167×103 J=2090 kJ



Q 46 :

The thermodynamic process, in which internal energy of the system remains constant is                [2023]

  • Isochoric

     

  • Isothermal

     

  • Adiabatic

     

  • Isobaric

     

(2)

T=constantU=constant



Q 47 :

The initial pressure and volume of an ideal gas are P0 and V0. The final pressure of the gas when the gas is suddenly compressed to volume V04 will be:  (Given γ= ratio of specific heats at constant pressure and at constant volume)                [2023]

  • P0(4)1/γ

     

  • P0(4)γ

     

  • P0

     

  • 4P0

     

(2)

As gas is suddenly compressed, the process is adiabatic.

Equation of gas for adiabatic process is PVγ=constant

  P1V1γ=P2V2γ

  P0V0γ=P2(V04)γ

  P2=P0(4)γ

Option (2) is correct.



Q 48 :

A thermodynamic system is taken through a cyclic process. The total work done in the process is                 [2023]

  • 100 J

     

  • 300 J

     

  • Zero

     

  • 200 J

     

(2)

On P-V scale, area of loop = work done

  W=+12(2)×300W=300 J



Q 49 :

A thermodynamic system is taken through the cyclic process ABC as shown in the figure. The total work done by the system during the cycle ABC is ________ J.   [2026]



300

 



Q 50 :

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1 to P2 is α Joule (P1=21.7 Pa and P2=30 PaCv=21 J/K.mol, R=8.3 J/mol.K). The value of α is _______.             [2026]

[IMAGE 60]

  • 28

     

  • 24

     

  • 15

     

  • 21

     

(4)