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Solution


Q.

A thermodynamic system is taken through a cyclic process. The total work done in the process is                 [2023]
1 100 J  
2 300 J  
3 Zero  
4 200 J  

Ans.

(2)

On P-V scale, area of loop = work done

⇒  W=+12(2)×300⇒W=300 J