Q.

A source supplies heat to a system at the rate of 1000 W. If the system performs work at a rate of 200 W, then the rate at which the internal energy of the system increases is       [2023]

1 800 W  
2 1200 W  
3 600 W  
4 500 W  

Ans.

(1)

dQ=dU+dW

dUdt=dQdt-dWdt

dUdt=1000-200=800 W