Electric Resistance and Simple Circuits | Physics JEE previous year questions with Solutions

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Q 11 :

A rectangular parallelopiped is measured as $1 cm \times 1 cm \times 100 cm$ . If its specific resistance is $3 \times 10^{- 7} Ω m$ , then the resistance between its two opposite rectangular faces will be _______ $\times 10^{- 7} Ω$ . [2023]

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(3)

$R = ρ \frac{l}{A} = \frac{3 \times 10^{- 7} \times (1 \times 10^{- 2})}{100 \times 1 \times 10^{- 4}} = 3 \times 10^{- 7} Ω$

Q 12 :

The current flowing through a conductor connected across a source is 2 A and 1.2 A at $0 ° C$ and $100 ° C$ respectively. The current flowing through the conductor at $50 ° C$ will be _______ $\times 10^{2} mA$ . [2023]

0%

(15)

$i_{0} R_{0} = i_{100} R_{100} [For same source]$

$\Rightarrow 2 R_{0} = 1.2 R_{0} [1 + 100 α]$ ...(i)

$\Rightarrow 1 + 100 α = \frac{5}{3}$

$\Rightarrow 50 α = \frac{1}{3}$

$∴$ $i_{50} R_{50} = i_{0} R_{0}$

$\Rightarrow i_{50} = \frac{i_{0} R_{0}}{R_{50}} = \frac{2 \times R_{0}}{R_{0} (1 + 50 α)} = \frac{2}{1 + \frac{1}{3}} = 1.5 A$

$\Rightarrow i_{50} = 15 \times 10^{2} mA$

Topic Question Set

Q 11 :

A rectangular parallelopiped is measured as $1 cm \times 1 cm \times 100 cm$ . If its specific resistance is $3 \times 10^{- 7} Ω m$ , then the resistance between its two opposite rectangular faces will be _______ $\times 10^{- 7} Ω$ . [2023]

0%

Q 12 :

The current flowing through a conductor connected across a source is 2 A and 1.2 A at $0 ° C$ and $100 ° C$ respectively. The current flowing through the conductor at $50 ° C$ will be _______ $\times 10^{2} mA$ . [2023]

0%

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