Electric Resistance and Simple Circuits | Physics JEE previous year questions with Solutions

Q 1 :
In the given circuit, the terminal potential difference of the cell is [2024]

4 V
2 V
3 V
1.5 V

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(2)

Current supplied by battery, $i = \frac{3}{1 + 2} = 1 A$

The terminal potential difference of the cell

$V = E - i r = 3 - 1 \times 1 = 2 V$

Q 2 :
A potential divider circuit is shown in figure. The output voltage $V_{0}$ is [2024]

4 V
2 mV
0.5 V
12 mV

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4

(3)

$R_{eq} = 4000 Ω$

$i = \frac{4}{4000} = \frac{1}{1000} A$

$V_{0} = (i) (500 Ω)$

$= \frac{1}{1000} \times 500 = 0.5 volt$

Q 3 :
The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

5 V
10 V
0 V
3 V

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4

(3)

$i = \frac{E_{eq}}{r_{eq}} = \frac{8 \times 5}{8 \times 0.2}$

$I = 25 A$

Reading of Voltmeter $V = E - i r = 5 - 0.2 \times 25 = 0$

Q 4 :
A galvanometer (G) of 2 $Ω$ resistance is connected in the given circuit. The ratio of charge stored in $C_{1}$ and $C_{2}$ is [2024]

$\frac{2}{3}$
$\frac{3}{2}$
$1$
$\frac{1}{2}$

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3

4

(4)

Resistance $R = 12 Ω$

Current $i = \frac{6}{12} = \frac{1}{2} A$

$\frac{q_{4 μ F}}{q_{6 μ F}} = \frac{4 \times 10^{- 6} \times 3}{6 \times 10^{- 6} \times 4} = \frac{1}{2}$

Q 5 :
The current flowing through the $1 Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is ______ . [2024]

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(25)

At junction $y$ ,

$\frac{y - 5}{2} + \frac{y - 0}{2} + \frac{y - (x - 10)}{1} = 0$

$y - 5 + x + 3 x - 40 - 4 y = 0$

$4 y - 2 x + 15 = 0$ ...(i)

At junction $x,$ $\frac{x - 5}{4} + \frac{x - 0}{4} + \frac{(x - 10) - y}{1} = 0$

$x - 5 + x + 4 x - 40 + 4 y = 0$

$6 x - 4 y - 45 = 0$ ...(ii)

$x = \frac{15}{2} V and y = 0$

$i_{1} = \frac{y - (x - 10)}{1} = \frac{0 - 7.5 + 10}{1}$

$\Rightarrow i_{1} = 2.5 A = \frac{n}{10} A \Rightarrow n = 25$

Q 6 :
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]

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(6)

$r_{eq} = r_{1} + r_{2} = (2 + 4) Ω = 6 Ω$

Current in the loop, $i = \frac{ε_{eq}}{r_{eq}} = \frac{6 V}{6 Ω} = 1 A$

Terminal potential difference of cell $E_{2} \Rightarrow E_{2} + i r_{2}$

$\Rightarrow [2 + (1) (4)] V \Rightarrow 6 V$

Q 7 :
Given below are two statements:

Statement-I : The equivalent emf of two nonideal batteries connected in parallel is smaller than either of the two emfs.

Statement-II : The equivalent internal resistance of two nonideal batteries connected in parallel is smaller than the internal resistance of either ofthe two batteries.

In the light of the above statements, choose the correct answer from the options given below. [2025]

Statement-I is true but Statement-II is false
Both Statement-I and Stratement-II are false
Both Statement-I and Statement-II are true
Statement-I is false but Statement-II is true

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(4)

In parallel connections,

$\frac{1}{r_{eq}} = \frac{1}{r_{1}} + \frac{1}{r_{2}} and \frac{E_{eq}}{r_{eq}} = \frac{E_{1}}{r_{1}} + \frac{E_{2}}{r_{2}}$

If $E_{1} = E_{2} and r_{1} = r_{2}$

$∴$ Statement-I is false.

$r_{eq}$ is less than both $r_{1}$ and $r_{2}$

$∴$ Statement -II is true.

Q 8 :
The value of current $I$ in the electrical circuit as given below, when potential at A is equal to the potential at B, will be ______ A. [2025]

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(2)

$V_{A} = V_{B} \Rightarrow$ the bridge is balanced

$\Rightarrow \frac{10}{R} = \frac{20}{40} \Rightarrow R = 20 Ω$

$\Rightarrow I = \frac{40}{20} = 2 A$

Q 9 :
In the figure shown below, a resistance of 150.4 $Ω$ is connected in series to an ammeter A of resistance 240 $Ω$ . A shunt resistance of 10 $Ω$ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA. [2025]

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(5)

$R_{eq} = R_{1} + R_{2}$

$R_{eq} = 150.4 + \frac{240 \times 10}{250}$

$= 150.4 + 9.6 = 160 Ω$

$I_{1} = \frac{I R_{2}}{240} = \frac{I \times 9.6}{240}$

$= \frac{20}{160} \times \frac{96}{2400} = \frac{1}{200} A$

$= 5 \times 10^{- 3} A = 5 mA$

Q 10 :
Two cells of emf 1 V and 2 V and internal resistance 2 $Ω$ and 1 $Ω$ , respectively, are connected in series with an external resistance of 6 $Ω$ . The total current in the circuit is $I_{1}$ . Now the same two cells in parallel configuration are connected to same external resistance. In this case, the total current drawn is $I_{2}$ . The value of $(\frac{I_{1}}{I_{2}})$ is $\frac{X}{3}$ . The value of X is _________. [2025]

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(4)

$I_{1} = \frac{ε_{1} + ε_{2}}{r_{1} + r_{2} + R} = \frac{1 + 2}{2 + 1 + 6} = \frac{3}{9} = \frac{1}{3} A$

$ε_{eq} = \frac{\frac{ε_{1}}{r_{1}} + \frac{ε_{2}}{r_{2}}}{\frac{1}{r_{1}} + \frac{1}{r_{2}}} = \frac{\frac{1}{2} + \frac{2}{1}}{\frac{1}{2} + \frac{1}{1}} = \frac{5}{3} V$

$r_{eq} = \frac{r_{1} r_{2}}{r_{1} + r_{2}} + R = \frac{2 \times 1}{3} + 6 = \frac{20}{3} Ω$

$I_{2} = \frac{ε_{eq}}{r_{eq}} = \frac{\frac{5}{3}}{\frac{20}{3}} = \frac{1}{4} A$

$\Rightarrow \frac{I_{1}}{I_{2}} = \frac{1}{3} \times \frac{4}{1} = \frac{4}{3}$

Topic Question Set

Q 1 :
In the given circuit, the terminal potential difference of the cell is [2024]

Q 2 :
A potential divider circuit is shown in figure. The output voltage $V_{0}$ is [2024]

Q 3 :
The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

Q 4 :
A galvanometer (G) of 2 $Ω$ resistance is connected in the given circuit. The ratio of charge stored in $C_{1}$ and $C_{2}$ is [2024]

Q 5 :
The current flowing through the $1 Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is ______ . [2024]

0%

Q 6 :
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]

0%

Q 8 :
The value of current $I$ in the electrical circuit as given below, when potential at A is equal to the potential at B, will be ______ A. [2025]

0%

Q 9 :
In the figure shown below, a resistance of 150.4 $Ω$ is connected in series to an ammeter A of resistance 240 $Ω$ . A shunt resistance of 10 $Ω$ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA. [2025]

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Topic Question Set

Q 1 : In the given circuit, the terminal potential difference of the cell is [2024]

Q 2 : A potential divider circuit is shown in figure. The output voltage V0 is [2024]

Q 3 : The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

Q 4 : A galvanometer (G) of 2Ω resistance is connected in the given circuit. The ratio of charge stored in C1 and C2 is [2024]

Q 5 : The current flowing through the 1Ω resistor is n10A. The value of n is ______ . [2024]

0%

Q 6 : Two cells are connected in opposition as shown. Cell E1 is of 8 V emf and 2Ω internal resistance; the cell E2 is of 2 V emf and 4Ω internal resistance. The terminal potential difference of cell E2 is ____ V. [2024]

0%

Q 8 : The value of current I in the electrical circuit as given below, when potential at A is equal to the potential at B, will be ______ A. [2025]

0%

Q 9 : In the figure shown below, a resistance of 150.4Ω is connected in series to an ammeter A of resistance 240Ω. A shunt resistance of 10Ω is connected in parallel with the ammeter. The reading of the ammeter is ______ mA. [2025]

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Q 1 :
In the given circuit, the terminal potential difference of the cell is [2024]

Q 2 :
A potential divider circuit is shown in figure. The output voltage $V_{0}$ is [2024]

Q 3 :
The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

Q 4 :
A galvanometer (G) of 2 $Ω$ resistance is connected in the given circuit. The ratio of charge stored in $C_{1}$ and $C_{2}$ is [2024]

Q 5 :
The current flowing through the $1 Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is ______ . [2024]

Q 6 :
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]

Q 8 :
The value of current $I$ in the electrical circuit as given below, when potential at A is equal to the potential at B, will be ______ A. [2025]

Q 9 :
In the figure shown below, a resistance of 150.4 $Ω$ is connected in series to an ammeter A of resistance 240 $Ω$ . A shunt resistance of 10 $Ω$ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA. [2025]