Electric Resistance and Simple Circuits | Physics JEE previous year questions with Solutions

Q 1 :
In the given circuit, the terminal potential difference of the cell is [2024]

4 V
2 V
3 V
1.5 V

1

2

3

4

(2)

Current supplied by battery, $i = \frac{3}{1 + 2} = 1 A$

The terminal potential difference of the cell

$V = E - i r = 3 - 1 \times 1 = 2 V$

Q 2 :
A potential divider circuit is shown in figure. The output voltage $V_{0}$ is [2024]

4 V
2 mV
0.5 V
12 mV

1

2

3

4

(3)

$R_{eq} = 4000 Ω$

$i = \frac{4}{4000} = \frac{1}{1000} A$

$V_{0} = (i) (500 Ω)$

$= \frac{1}{1000} \times 500 = 0.5 volt$

Q 3 :
The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

5 V
10 V
0 V
3 V

1

2

3

4

(3)

$i = \frac{E_{eq}}{r_{eq}} = \frac{8 \times 5}{8 \times 0.2}$

$I = 25 A$

Reading of Voltmeter $V = E - i r = 5 - 0.2 \times 25 = 0$

Q 4 :
A galvanometer (G) of 2 $Ω$ resistance is connected in the given circuit. The ratio of charge stored in $C_{1}$ and $C_{2}$ is [2024]

$\frac{2}{3}$
$\frac{3}{2}$
$1$
$\frac{1}{2}$

1

2

3

4

(4)

Resistance $R = 12 Ω$

Current $i = \frac{6}{12} = \frac{1}{2} A$

$\frac{q_{4 μ F}}{q_{6 μ F}} = \frac{4 \times 10^{- 6} \times 3}{6 \times 10^{- 6} \times 4} = \frac{1}{2}$

Q 5 :
The current flowing through the $1 Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is ______ . [2024]

0%

(25)

At junction $y$ ,

$\frac{y - 5}{2} + \frac{y - 0}{2} + \frac{y - (x - 10)}{1} = 0$

$y - 5 + x + 3 x - 40 - 4 y = 0$

$4 y - 2 x + 15 = 0$ ...(i)

At junction $x,$ $\frac{x - 5}{4} + \frac{x - 0}{4} + \frac{(x - 10) - y}{1} = 0$

$x - 5 + x + 4 x - 40 + 4 y = 0$

$6 x - 4 y - 45 = 0$ ...(ii)

$x = \frac{15}{2} V and y = 0$

$i_{1} = \frac{y - (x - 10)}{1} = \frac{0 - 7.5 + 10}{1}$

$\Rightarrow i_{1} = 2.5 A = \frac{n}{10} A \Rightarrow n = 25$

Q 6 :
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]

0%

(6)

$r_{eq} = r_{1} + r_{2} = (2 + 4) Ω = 6 Ω$

Current in the loop, $i = \frac{ε_{eq}}{r_{eq}} = \frac{6 V}{6 Ω} = 1 A$

Terminal potential difference of cell $E_{2} \Rightarrow E_{2} + i r_{2}$

$\Rightarrow [2 + (1) (4)] V \Rightarrow 6 V$

Topic Question Set

Q 1 :
In the given circuit, the terminal potential difference of the cell is [2024]

Q 2 :
A potential divider circuit is shown in figure. The output voltage $V_{0}$ is [2024]

Q 3 :
The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

Q 4 :
A galvanometer (G) of 2 $Ω$ resistance is connected in the given circuit. The ratio of charge stored in $C_{1}$ and $C_{2}$ is [2024]

Q 5 :
The current flowing through the $1 Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is ______ . [2024]

0%

Q 6 :
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]

0%

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Topic Question Set

Q 1 : In the given circuit, the terminal potential difference of the cell is [2024]

Q 2 : A potential divider circuit is shown in figure. The output voltage V0 is [2024]

Q 3 : The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

Q 4 : A galvanometer (G) of 2Ω resistance is connected in the given circuit. The ratio of charge stored in C1 and C2 is [2024]

Q 5 : The current flowing through the 1Ω resistor is n10A. The value of n is ______ . [2024]

0%

Q 6 : Two cells are connected in opposition as shown. Cell E1 is of 8 V emf and 2Ω internal resistance; the cell E2 is of 2 V emf and 4Ω internal resistance. The terminal potential difference of cell E2 is ____ V. [2024]

0%

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Q 1 :
In the given circuit, the terminal potential difference of the cell is [2024]

Q 2 :
A potential divider circuit is shown in figure. The output voltage $V_{0}$ is [2024]

Q 3 :
The reading in the ideal voltmeter (V) shown in the given circuit diagram is [2024]

Q 4 :
A galvanometer (G) of 2 $Ω$ resistance is connected in the given circuit. The ratio of charge stored in $C_{1}$ and $C_{2}$ is [2024]

Q 5 :
The current flowing through the $1 Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is ______ . [2024]

Q 6 :
Two cells are connected in opposition as shown. Cell $E_{1}$ is of 8 V emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of 2 V emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ____ V. [2024]