Q 1 :

In the given circuit, the terminal potential difference of the cell is              [2024]

  • 4 V

     

  • 2 V

     

  • 3 V

     

  • 1.5 V

     

(2)

Current supplied by battery, i=31+2=1A

The terminal potential difference of the cell

V=E-ir=3-1×1=2V

 



Q 2 :

A potential divider circuit is shown in figure. The output voltage V0 is                     [2024]

  • 4 V

     

  • 2 mV

     

  • 0.5 V

     

  • 12 mV

     

(3)

Req=4000Ω

i=44000=11000A

V0=(i)(500Ω)

       =11000×500=0.5 volt

 



Q 3 :

The reading in the ideal voltmeter (V) shown in the given circuit diagram is             [2024]

  • 5 V

     

  • 10 V

     

  • 0 V

     

  • 3 V

     

(3)

i=Eeqreq=8×58×0.2

I=25A

Reading of Voltmeter V=E-ir=5-0.2×25=0



Q 4 :

A galvanometer (G) of 2Ω resistance is connected in the given circuit. The ratio of charge stored in C1 and C2 is         [2024]

  • 23

     

  • 32

     

  • 1

     

  • 12

     

(4)

Resistance R=12Ω

Current i=612=12A

q4μFq6μF=4×10-6×36×10-6×4=12



Q 5 :

The current flowing through the 1Ω resistor is n10A. The value of n is ______ .                    [2024]



(25)

At junction y,

y-52+y-02+y-(x-10)1=0

y-5+x+3x-40-4y=0

4y-2x+15=0                                       ...(i)

At junction x, x-54+x-04+(x-10)-y1=0

x-5+x+4x-40+4y=0

6x-4y-45=0                                    ...(ii)

x=152V and y=0

i1=y-(x-10)1=0-7.5+101

i1=2.5A=n10An=25



Q 6 :

Two cells are connected in opposition as shown. Cell E1 is of 8 V emf and 2Ω internal resistance; the cell E2 is of 2 V emf and 4Ω internal resistance. The terminal potential difference of cell E2 is ____ V.            [2024]



(6)

req=r1+r2=(2+4)Ω=6Ω

Current in the loop, i=εeqreq=6V6Ω=1A

Terminal potential difference of cell E2E2+ir2

[2+(1)(4)]V6V



Q 7 :

Given below are two statements:

Statement-I : The equivalent emf of two nonideal batteries connected in parallel is smaller than either of the two emfs.

Statement-II : The equivalent internal resistance of two nonideal batteries connected in parallel is smaller than the internal resistance of either ofthe two batteries.

In the light of the above statements, choose the correct answer from the options given below.         [2025]

  • Statement-I is true but Statement-II is false

     

  • Both Statement-I and Stratement-II are false

     

  • Both Statement-I and Statement-II are true

     

  • Statement-I is false but Statement-II is true

     

(4)

In parallel connections,

1req=1r1+1r2 and Eeqreq=E1r1+E2r2

If E1=E2 and r1=r2

 Statement-I is false.

req is less than both r1 and r2

 Statement -II is true.



Q 8 :

The value of current I in the electrical circuit as given below, when potential at A is equal to the potential at B, will be ______ A.          [2025]



(2)

VA=VB  the bridge is balanced

 10R=2040  R=20Ω

 I=4020=2A



Q 9 :

In the figure shown below, a resistance of 150.4Ω is connected in series to an ammeter A of resistance 240Ω. A shunt resistance of 10Ω is connected in parallel with the ammeter. The reading of the ammeter is ______ mA.          [2025]



(5)

Req=R1+R2

Req=150.4+240×10250

       =150.4+9.6=160Ω

I1=IR2240=I×9.6240

     =20160×962400=1200A

     =5×103A=5 mA



Q 10 :

Two cells of emf 1 V and 2 V and internal resistance 2 Ω and 1 Ω, respectively, are connected in series with an external resistance of 6 Ω. The total current in the circuit is I1. Now the same two cells in parallel configuration are connected to same external resistance. In this case, the total current drawn is I2. The value of (I1I2) is X3. The value of X is _________.          [2025]



(4)

I1=ε1+ε2r1+r2+R=1+22+1+6=39=13A

εeq=ε1r1+ε2r21r1+1r2=12+2112+11=53V

req=r1r2r1+r2+R=2×13+6=203Ω

I2=εeqreq=53203=14A

 I1I2=13×41=43



Q 11 :

Figure shows a part of an electric circuit. The potentials at points a, b and c are 30 V, 12 V and 2 V respectively. The current through the 20Ω resistor will be.       [2023]

  • 0.4 A

     

  • 0.2 A

     

  • 0.6 A

     

  • 1.0 A

     

(1)

Sum of current at junction point will be zero:

x-3010+x-1220+x-230=0

x(110+120+130)=3010+1220+230

x(6+3+260)=180+36+460

x=22011=20 V

  Current through 20Ω, I20Ω=x-1220

I20Ω=20-1220=25=0.4 A



Q 12 :

In this figure the resistance of the coil of galvanometer G is 2Ω. The emf of the cell is 4 V.  The ratio of potential difference across C1 and C2 is           [2023]

  • 54

     

  • 1

     

  • 34

     

  • 45

     

(4)

At steady state, current in the circuit is

i=4V6+2+8=14 A

Voltage across C1 is

V1=VAC=i(6Ω+2Ω)=14×8=2 V

Voltage across C2 is

V2=VBD=i(2Ω+8Ω)=14×10=2.5 V

V1V2=22.5=45



Q 13 :

The current flowing through R2 is                            [2023]

  • 23A

     

  • 14A

     

  • 12A

     

  • 13A

     

(4)

Req=4Ω

i=84=2 A

i1=2×33+6=23 A

i2=2/32=13A



Q 14 :

In the following circuit, the magnitude of current I1, is _______ A.              [2023]



(1.5)

Junction law at A,

       x-(y+5)1+x-22+x-02=0                      ...(i)

Junction law at B,

       y+5-x1+y-01+y-21=0                        ...(ii)

On solving equation (i) and equation (ii),

         x=3 and y=0

At D junction, I1=i1+i2

      I1=y-01+x-02=0-01+3-02

I1=1.5 A



Q 15 :

Two identical cells, when connected either in parallel or in series, give the same current in an external resistance 5Ω. The internal resistance of each cell will be _____ Ω[2023]



(5)

εr+5×5=200x                          ...(i)

ε×15r+15=300x                             ...(ii)

r=5Ω



Q 16 :

In the given circuit, the value of |I1+I3I2| is __________ .          [2023]



(2)

I1=I2=20-1010=1A

I3=1A |I1+I3I2|=2



Q 17 :

Two cells are connected between points A and B as shown. Cell 1 has emf of 12 V and internal resistance of 3Ω. Cell 2 has emf of 6 V and internal resistance of 6Ω. An external resistor R of 4Ω is connected across A and B. The current flowing through R will be __________ A.                 [2023]



(1)

Eeq=123-6613+16=6 V

Req=2 Ω  and  R=4 Ω

So, i=62+4=1A



Q 18 :

In the circuit diagram shown in the figure given below, the current flowing through resistance 3Ω is x3 A. The value of x is ________.                [2023]



(1)

E=E2-E1=8-4=4 V

13+16=12=1R

R=2Ω

The current supplied by battery E,

I=E1.5+4.5+2=48=0.5 A

Hence current in 3Ω resistance,

I1=(63+6)×0.5=13A

I1=x3=13

 x=1



Q 19 :

Two identical cells each of emf 1.5 V are connected in series across a 10Ω resistance. An ideal voltmeter connected across the 10Ω resistance reads 1.5 V. The internal resistance of each cell is __________ Ω.                     [2023]



(5)

V=1×10

1.5=(310+2r)×10

r=5Ω



Q 20 :

In the circuit shown, the energy stored in the capacitor is nμJ. The value of n is _______.                  [2023]



(75)

I1=123+9=1A

I2=124+2=2A

VA-VC=3I1=3V                              ...(i)

VA-VD=2×4=8V                           ...(ii)

Subtracting eq. (i) from eq. (ii),

VC-VD=5V  V=5V

U=12CV2=12×6×52=75 μJ



Q 21 :

A network of four resistances is connected to a 9 V battery, as shown in the figure. The magnitude of voltage difference between the points A and B is __________ V.    [2023]



(3)

In the circuit, I=93=3A

VC-VA=2×1.5=3                     ...(i)

VC-VB=4×1.5=6                     ...(ii)

Equation (ii) - Equation (i)

VA-VB=6-3=3 V



Q 22 :

Two resistors 2Ω and 3Ω are connected in the gaps of a bridge as shown in the figure. The null point is obtained with the contact of jockey at some point on wire XY. When an unknown resistor is connected in parallel with 3Ω resistor, the null point is shifted by 22.5 cm toward Y. The resistance of the unknown resistor is _____ Ω.       [2026]

  • 1

     

  • 4

     

  • 3

     

  • 2

     

(4)

Initially, 23=x100-x

x=40 cm

Now when R connected in parallel

23R3+R=40+22.560-22.5=62.537.5

 R=2Ω



Q 23 :

Two resistors of 100Ω each are connected in series with a 9 V battery. A voltmeter of 400Ω resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is ________ V.                  [2026]

  • 4

     

  • 3

     

  • 2

     

  • 4.5

     

(1)

Current in circuit

I=EReq

Req=100+400×100400+100=180Ω

 I=9180=120 A

Reading of voltmeter=V=I×80=120×80=4 V



Q 24 :

A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances (R1=R2=R3=R4) When R3 resistance is heated to some temperature, its resistance value has gone up by 10% The potential difference (Va-Vb) (after R3 is heated) is ______ V.    [2026]

  • 0.95

     

  • 2

     

  • 0

     

  • 1.06

     

(1)

VA=V2

VB=V2·IR×R=V2.1

 VA-VB=V[12-12.1]

VA-VB=0.12×2.1×40

VA-VB=44.2=0.95



Q 25 :

A battery with EMF E and internal resistance r is connected across a resistance R. The power consumption in R will be maximum when:   [2026]

  • R = r

     

  • R = 2r

     

  • R = r/2

     

  • R=2r

     

(1)

For maximum power drawn across load

Resistance RLoad=Rinternal

R=r



Q 26 :

For the two cells having same EMF E and internal resistance r, the current passing through the external resistor 6Ω is same when both the cells are connected either in parallel or in series. The value of internal resistance r is ______ Ω.        [2026]

  • 6

     

  • 9

     

  • 3

     

  • 4

     

(1)

In series, i1=2E6+2r

In parallel, i2=E6+r2

i1=i22E6+2r=E6+r2

12+r=6+2r

r=6Ω