The current flowing through a conductor connected across a source is 2 A and 1.2 A at 0°C and 100°C respectively. The current flowing through the conductor at 50°C will be _______ ×102 mA. [2023]
(15)
i0R0=i100R100 [For same source]
⇒2R0=1.2R0[1+100α] ...(i)
⇒1+100α=53
⇒50α=13
∴ i50R50=i0R0
⇒i50=i0R0R50=2×R0R0(1+50α)=21+13=1.5 A
⇒i50=15×102 mA