Q 1 :    

The electric field between the two parallel plates of a capacitor of 1.5 μF capacitance drops to one third of its initial value in 6.6 μs when the plates are connected by a thin wire.

The resistance of this wire is __________ Ω. (Given, log 3 = 1.1)                [2024]



(4)     E=QAϵ0EQE=E0e-t/RC

        t=RClnE0E6.6×10-6=R(1.5×10-6)ln3

       R=66151ln3=6615×1.1=4Ω

 



Q 2 :    

The charge accumulated on the capacitor connected in the following circuit is ___________ μC. (Given C = 150 μF)         [2024]

[IMAGE 184]



(400)

VA+103(1)-6(1)=VB

[IMAGE 185]

VA-VB=6-103=83 volt

Q=C(VA-VB)=150×83=400μC



Q 3 :    

In the given figure, the charge stored in 6μF capacitor, when points A and B are joined by a connecting wire is ______ μC       [2024]

[IMAGE 186]



(36)

At steady state, capacitor behaves as an open circuit and current flows in circuit as shown in the diagram.

[IMAGE 187]

Req=9Ω

i=9V9Ω=1A

ΔV6Ω=1×6=6V

VA=3V

So, potential difference across 6μF is 6 V.

Hence Q=CΔV=6×6×10-6C=36μC

 



Q 4 :    

In an electrical circuit drawn below the amount of charge stored in the capacitor is ________ μC.                [2024]

[IMAGE 188]



(60)

[IMAGE 189]

inet=ΔVReq

       =ΔVReq=VR1+R3=104+6=1A

VA'-VB'=iR3=1×6=6V

q=CΔV=C(VA-VB)=10×6=60μC