Q 1 :    

The electric field between the two parallel plates of a capacitor of 1.5 μF capacitance drops to one third of its initial value in 6.6 μs when the plates are connected by a thin wire.

The resistance of this wire is __________ Ω. (Given, log 3 = 1.1)                [2024]



(4)     E=QAϵ0EQE=E0e-t/RC

        t=RClnE0E6.6×10-6=R(1.5×10-6)ln3

       R=66151ln3=6615×1.1=4Ω