Q 1 :    

The electric field between the two parallel plates of a capacitor of 1.5 μF capacitance drops to one third of its initial value in 6.6 μs when the plates are connected by a thin wire.

The resistance of this wire is __________ Ω. (Given, log 3 = 1.1)                [2024]



(4)     E=QAϵ0EQE=E0e-t/RC

        t=RClnE0E6.6×10-6=R(1.5×10-6)ln3

       R=66151ln3=6615×1.1=4Ω

 



Q 2 :    

The charge accumulated on the capacitor connected in the following circuit is ___________ μC. (Given C = 150 μF)         [2024]



(400)

VA+103(1)-6(1)=VB

VA-VB=6-103=83 volt

Q=C(VA-VB)=150×83=400μC



Q 3 :    

In the given figure, the charge stored in 6μF capacitor, when points A and B are joined by a connecting wire is ______ μC       [2024]



(36)

At steady state, capacitor behaves as an open circuit and current flows in circuit as shown in the diagram.

Req=9Ω

i=9V9Ω=1A

ΔV6Ω=1×6=6V

VA=3V

So, potential difference across 6μF is 6 V.

Hence Q=CΔV=6×6×10-6C=36μC

 



Q 4 :    

In an electrical circuit drawn below the amount of charge stored in the capacitor is ________ μC.                [2024]



(60)

inet=ΔVReq

       =ΔVReq=VR1+R3=104+6=1A

VA'-VB'=iR3=1×6=6V

q=CΔV=C(VA-VB)=10×6=60μC



Q 5 :    

Identify the valid statements relevant to the given circuit at the instant when the key is closed.

A. There will be no current through resistor R.

B. There will be maximum current in the connecting wires.

C. Potential difference between the capacitor plates A and B is minimum.

D. Charge on the capacitor plates is minimum.

Choose the correct answer from the options given below.:         [2025]

  • C, D only

     

  • B, C, D only

     

  • A, C only

     

  • A, B, D only

     

(2)

Capacitor behaves as a short circuit at t = 0

So current will be maximum.

Charge on capacitor will be zero.

Potential difference across capacitor will be zero.



Q 6 :    

At steady state the charge on the capacitor, as shown in the circuit below, is ______ μC.          [2025]



(16)

i=(525)A

V10Ω=Vc=525×10=2 V

Q=8×2=16 μC



Q 7 :    

The net current flowing in the given circuit is ______ A.          [2025]



(1)

The capacitor behaves as open circuit, I=VReq

Req=2Ω

 I=22=1A