(22)             Velocity ($v$) of electron in $n^{th}$ Bohr orbit of a single electron specie with atomic no. Z is given by:

                     $\nu =2.18\times {10}^8\frac{Z}{n}\mathrm{cm}/\mathrm{s}$

                     For hydrogen atom, Z = 1 and for first orbit n = 1.

                     $\nu =2.18\times {10}^8\times \frac{1}{1}\mathrm{cm}/\mathrm{s}=2.18\times {10}^{6}m/\mathrm{s}\simeq 22\times {10}^{5}m/\mathrm{s}$

(34)               For an electron present in a single electron species in any of the orbits,

                      Total energy : kinetic energy : potential energy = -1 : +1 : -2

                       Thus if total energy is -3.4 eV, then kinetic energy is +3.4 eV = $34\times {10}^{-1}$ eV.