The energy of an electron in first Bohr orbit of H-atom is –13.6 eV. The magnitude of energy value of electron in the first excited state of is ______ eV. (nearest integer value) [2025]

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Solution

Q.
The energy of an electron in first Bohr orbit of H-atom is –13.6 eV. The magnitude of energy value of electron in the first excited state of ${Be}^{3 +}$ is ______ eV. (nearest integer value) [2025]

Ans.
(54)

$E = - 13.6 \frac{Z^{2}}{n^{2}} eV$

For ${Be}^{3 +}$ , Z = 4. For first excited state, $n$ = 2.

$E = - 13.6 \frac{4^{2}}{2^{2}} eV = - 54.4 eV$

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