Q 1 :    

Match List I with List II

  LIST I (Spectral Series for Hydrogen)   LIST II (Spectral Region/Higher Energy State)
A. Lyman I. Infrared region
B. Balmer II. UV region
C. Paschen III. Infrared region
D. Pfund IV. Visible region

 

Choose the correct answer from the options given below:               [2024]

  • A-I, B-III, C-II, D-IV

     

  • A-II, B-III, C-I, D-IV

     

  • A-II, B-IV, C-III, D-I

     

  • A-I, B-II, C-III, D-IV

     

(3)             

                 For hydrogen atom,

                  (i) Lyman series lies in ultraviolet region.

                  (ii) First four lines of Balmer series are in visible region and higher ones are in ultraviolet region.

                  (iii) Paschen and Pfund series are in infrared region.

 



Q 2 :    

Number of spectral lines obtained in He+ spectra, when an electron makes transition from fifth excited state to first excited state will be _______ .             [2024]



(10)                 

Fifth excited state means sixth shell and first excited state means second shell. Thus transition is from 6th to 2nd shell. Number of spectral lines when electrons make transition from n2 energy level to n1 energy level in a sample of gas atoms is:

                       (n2-n1)(n2-n1+1)2=(6-2)(6-2+1)2=10

 



Q 3 :    

Given below are two statements:

Statement I: A spectral line will be observed for a 2px2py transition.

Statement II: 2px and 2py are degenerate orbitals.

In the light of the above statements, choose the correct answer from the options given below:                 [2025]

  • Both Statement I and Statement II are true

     

  • Statement I is true but Statement II is false

     

  • Both Statement I and Statement II are false

     

  • Statement I is false but Statement II is true

     

(4)

Spectral line is observed when an electron makes a transition between two orbitals of different energy. As 2px and 2py have same energy (called degenerated orbitals), no spectral line is observed by transition of an electron between these two orbitals.

 



Q 4 :    

Heat treatment of muscular pain involves radiation of wavelength of about 900 nm. Which spectral line of H atom is suitable for this? 

Given: Rydberg constant RH=105cm-1, h=6.6×10-34Js, c=3×108m/s                  [2025]

  • Lyman series, 1

     

  • Balmer series, 2

     

  • Paschen series, 53

     

  • Paschen series, 3

     

(4)

λ=900 nm=900×10-9m

   =900×10-9m×100 cm=9×10-5cm

RH=105cm-1

By Rydberg’s equation:

1λ=RHZ2(1n12-1n22)

19×10-5cm=105cm-1×(1)2(1n12-1n22)

(1n12-1n22)=19

n1=3,  n2=