Q 1 :    

If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is x2 times its original time period. Then the value of x is         [2024]
 

  • 3

     

  • 2

     

  • 23

     

  • 4

     

(2)

Time period of a simple pendulum, T=2πlg            ...(i)

T'=2πl2g                                                                ...(ii)

T'=x2T  (given)

  2πl2g=x2×2πlg    x=2