Q 11 :

A person travelling on a straight line moves with a uniform velocity v1 for a distance x and with a uniform velocity v2 for the next 32x distance. The average velocity in this motion is 507 m/s. If v1 is 5 m/s then v2 = __________ m/s.          [2025]



(10)

vavg=x1+x2t1+t2

 507=x+3x2x5+3x2v2

 507=5/215+32v2

 v2=10 m/s



Q 12 :

The distance travelled by a particle is related to time t as x=4t2. The velocity of the particle at t = 5 s is                   [2023]

  • ms-1

     

  • 20 ms-1

     

  • 25 ms-1

     

  • 40 ms-1

     

(4)

x=4t2

v=dxdt=8t

At t=5 s,  

      v=8×5=40 m/s



Q 13 :

A vehicle travels 4 km with speed of 3 km/h and another 4 km with speed of 5 km/h, then its average speed is           [2023]

  • 4.25 km/h

     

  • 3.50 km/h

     

  • 4.00 km/h

     

  • 3.75 km/h

     

(4)

2Vav=13+15=815

 Vav=154=3.75 km/h