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Solution


Q.

The position of a particle related to time is given by x=(5t2-4t+5)m. The magnitude of velocity of the particle at t=2 s will be:           [2023]
1 10 ms-1  
2 14 ms-1  
3 16 ms-1  
4 6 ms-1  

Ans.

(3)

x=5t2-4t+5

v=10t-4

At t=2 s,  v=16 m/s