Q.

A car travels a distance of 'x' with speed v1 and then the same distance 'x' with speed v2 in the same direction. The average speed of the car is:             [2023]

1 v1v22(v1+v2)  
2 2xv1+v2  
3 2v1v2v1+v2  
4 v1+v22  

Ans.

(3)

Vavg=S+SSV1+SV2=2V1V2V1+V2