The distance travelled by an object in time t is given by s=(2.5)t2. The instantaneous speed of the object at t = 5 s will be: [2023]
(4)
Distance (s)=(2.5)t2
Speed (v)=dsdt=ddt{(2.5)t2}
v=5t
At t=5, v=5×5=25 m/s
Option (4) is correct