Q 1 :    

An alternating voltage of amplitude 40 V and frequency 4 kHz is applied directly across the capacitor of 12 μF. The maximum displacement current between the plates of the capacitor is nearly               [2024]

  • 12 A

     

  • 13 A

     

  • 10 A

     

  • 8 A

     

(A)      Displacement current is same as conduction current in capacitor.

           XC=1ωC=12πfC

           =12π×4×103×12×10-6=3.317Ω

           I=VXC=403.317=12A



Q 2 :    

Electromagnetic waves travel in a medium with speed of 1.5×108 ms-1. The relative permeability of the medium is 2.0. The relative permittivity will be:      [2024]

  • 2

     

  • 1

     

  • 5

     

  • 4

     

(A)       Speed of light in vacuum=1μ0ϵ0=3×108

            Speed of light in medium=1μ00·μrr=32×108

           Also, given, ϵr=2, therefore, μr=2

 



Q 3 :    

A plane EM wave is propagating along x direction. It has a wavelength of 4 mm. If electric field is in y direction with the maximum magnitude of 6O Vm-1, the equation for magnetic field is          [2024]

  • Bz=60sin[π2(x-3×108t)]k^T

     

  • Bz=2×10-7sin[π2×103(x-3×108t)]k^T

     

  • Bx=60sin[π2(x-3×108t)]i^T

     

  • Bz=2×10-7sin[π2(x-3×108t)]k^T

     

(B)        λ=4mm=4×10-3m

             K=2π4×10-3=π2×103·m-1

             ω=v×K=3×108×π2×103=3π2×1011rad/s

             Electric field y direction

             Propagation field x direction

             Mgnetic field z direction

             E^×B^=c^ and B0=E0c=2×10-7T

            Bz=2×10-7sin[π2×103(x-3×108t)]k^T



Q 4 :    

The magnetic field in a plane electromagnetic wave is By=(3.5×10-7)sin(1.5×103x+0.5×1011t)T. The corresponding electric field will be             [2024]

  • Ey=1.17sin(1.5×103x+0.5×1011t)Vm-1

     

  • Ez=105sin(1.5×103x+0.5×1011t)Vm-1

     

  • Ez=1.17sin(1.5×103x+0.5×1011t)Vm-1

     

  • Ey=10.5sin(1.5×103x+0.5×1011t)Vm-1

     

(B)       E0=B0c

            EZ=3×108×(3.5×10-7)sin(1.5×103x+0.5×1011t)

           Ez=105sin(1.5×103x+0.5×1011t)Vm-1

 



Q 5 :    

Match Column I with Column II

  Column I   Column II
A. Bdl=μ0ic+μ0ϵ0dΦEdt I. Gauss' law for electricity
B. Edl=dΦBdt II. Gauss' law for magnetism
C. EdA=Qϵ0 III. Faraday law
D. BdA=0 IV. Ampere-Maxwell law

 

Choose the correct answer from the options given below            [2024]

  • A-IV, B-I, C-III, D-II

     

  • A-II, B-III, C-I, D-IV

     

  • A-IV, B-III, C-I, D-II

     

  • A-I, B-II, C-III, D-IV

     

(C)          Ampere-Maxwell law, Bdl=μ0ic+μ0ϵ0dΦEdt

               Faraday law,  Edl=dΦBdt

               Gauss' law for electricity EdA=Qϵ0

               Gauss' law for magnetism BdA=0

 



Q 6 :    

A plane electromagnetic wave of frequency 35 MHz travels in free space along the X-direction. At a particular point (in space and time) E=9.6j^V/m. The value of magnetic field at this point is           [2024]

  • 9.6j^T

     

  • 3.2×10-8i^T

     

  • 3.2×10-8k^T

     

  • 9.6×10-8k^T

     

(C)      EB=3×108

           B=E3×108=9.63×108

           B=3.2×10-8TB^

               =i^×j^=k^

            So, B=3.2×10-8k^T

 



Q 7 :    

The electric field of an electromagnetic wave in free space is represented as E=E0cos(ωt-kz)i^.

The corresponding magnetic induction vector will be :            [2024]

  • B=E0ccos(ωt-kz)j^

     

  • B=E0ccos(ωt-kz)j^

     

  • B=E0ccos(ωt+kz)j^

     

  • B=E0ccos(ωt+kz)j^

     

(B)    Given E=E0cos(ωt-kz)i^

         E0=B0c,(B0=E0c)

        Also E and B are in same phase.

 



Q 8 :    

Match List I with List II

  List I   List II
A Gauss's Law of Magnetostatics I Eda=1ϵ0ρdV
B Faraday's law of electromagnetic induction II Bda=0
C Ampere's Law III Edl=ddtBda
D Gauss's law of Electrostatics IV Bdl=μ0I

 

Choose the correct answer from the options given below:                  [2024]

  • A-I, B-III, C-IV, D-II

  • A-III, B-IV, C-I, D-II

  • A-IV, B-II, C-III, D-I

  • A-II, B-III, C-IV, D-I

     

(D)        (A) Gauss of magnetostatics Bda=0                  (II)

              (B) Faraday's law Edt=-ddtBda         (III)

              (C) Ampere's law Bdt=μ0I                                   (IV)

              (D) Gauss of electro Eda=1ϵ0ρdV              (I)

 



Q 9 :    

Given below are two statements:

 

Statement I: Electromagnetic waves carry energy as they travel through space and this energy is equally shared by the electric and magnetic fields.

 

Statement II: When electromagnetic waves strike a surface, a pressure is exerted on the surface.

 

In the light of the above statements, choose the most appropriate answer from the options given below:          [2024]

  • Statement I is incorrect but Statement II is correct

     

  • Both Statement I and Statement II are correct.

     

  • Both Statement I and Statement II are incorrect.

     

  • Statement I is correct but Statement II is incorrect.

     

(B)       12ϵ0E2=B22μ0

 



Q 10 :    

If frequency of electromagnetic wave is 60 MHz and it travels in air along z-direction, then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other, and the wavelength of the wave (in m) is:           [2024]

  • 2.5

     

  • 10

     

  • 5

     

  • 2

     

(C)      Speed=Wavelength×Frequency

            λ=Cf=3×10860×106=5m