Electromagnetic Waves | Physics JEE Main questions with Solutions

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Topic Question Set

Q 1 :
Arrange the following in the ascending order of wavelength:

A. Gamma rays ( $λ_{1}$ )

B. x-rays ( $λ_{2}$ )

C. Infrared waves ( $λ_{3}$ )

D. Microwaves ( $λ_{4}$ )

Choose the most appropriate answer from the options given below [2024]

$λ_{4} < λ_{3} < λ_{1} < λ_{2}$
$λ_{2} < λ_{1} < λ_{4} < λ_{3}$
$λ_{4} < λ_{3} < λ_{2} < λ_{1}$
$λ_{1} < λ_{2} < λ_{3} < λ_{4}$

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2

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4

(4)

Order of wavelength

gamma rays < x-rays < infrared < microwaves

$\Rightarrow λ_{1} < λ_{2} < λ_{3} < λ_{4}$

Q 2 :
Match List-I with List-II:

List-I

(EM-Wave)

List-II

(Wavelength Range)

A Infra-red (I) $10^{- 3}$ nm

B Ultraviolet (II) 400 nm to 1 nm

C X-rays (III) 1 mm to 700 nm

D Gamma rays (IV) 1 nm to $10^{- 3}$ nm

Choose the correct answer from the options give below [2024]

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

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4

(3)

Infrared is the least energetic thus having biggest wavelength $(λ)$ and gamma rays are most energetic thus having smallest wave length $(λ)$ .

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