The magnetic field in a plane electromagnetic wave is The corresponding electric field will be

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
The magnetic field in a plane electromagnetic wave is $B_{y} = (3.5 \times 10^{- 7}) \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) T .$ The corresponding electric field will be [2024]

1 $E_{y} = 1.17 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

2 $E_{z} = 105 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

3 $E_{z} = 1.17 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

4 $E_{y} = 10.5 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

Ans.
(2)

$E_{0} = B_{0} c$

$E_{Z} = 3 \times 10^{8} \times (3.5 \times 10^{- 7}) \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t)$

$E_{z} = 105 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

Solution

Q.
The magnetic field in a plane electromagnetic wave is $B_{y} = (3.5 \times 10^{- 7}) \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) T .$ The corresponding electric field will be [2024]

1 $E_{y} = 1.17 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

2 $E_{z} = 105 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

3 $E_{z} = 1.17 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

4 $E_{y} = 10.5 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

Ans.
(2)

$E_{0} = B_{0} c$

$E_{Z} = 3 \times 10^{8} \times (3.5 \times 10^{- 7}) \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t)$

$E_{z} = 105 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

Want Us to Email you About Special Offers & Updates?

Solution

Q. The magnetic field in a plane electromagnetic wave is By=(3.5×10-7)sin(1.5×103x+0.5×1011t)T. The corresponding electric field will be [2024]

1 Ey=1.17sin(1.5×103x+0.5×1011t) Vm-1

2 Ez=105sin(1.5×103x+0.5×1011t) Vm-1

3 Ez=1.17sin(1.5×103x+0.5×1011t) Vm-1

4 Ey=10.5sin(1.5×103x+0.5×1011t) Vm-1

Ans. (2) E0=B0c EZ=3×108×(3.5×10-7)sin(1.5×103x+0.5×1011t) Ez=105sin(1.5×103x+0.5×1011t) Vm-1

Want Us to Email you About Special Offers & Updates?

Q.
The magnetic field in a plane electromagnetic wave is $B_{y} = (3.5 \times 10^{- 7}) \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) T .$ The corresponding electric field will be [2024]

1 $E_{y} = 1.17 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

2 $E_{z} = 105 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

3 $E_{z} = 1.17 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

4 $E_{y} = 10.5 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$

Ans.
(2)

$E_{0} = B_{0} c$

$E_{Z} = 3 \times 10^{8} \times (3.5 \times 10^{- 7}) \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t)$

$E_{z} = 105 \sin (1.5 \times 10^{3} x + 0.5 \times 10^{11} t) V m^{- 1}$