A plane electromagnetic wave of frequency 35 MHz travels in free space along the X-direction. At a particular point (in space and time) . The value of magnetic field at this point is

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Q.
A plane electromagnetic wave of frequency 35 MHz travels in free space along the X-direction. At a particular point (in space and time) $\vec{E} = 9.6 \hat{j} V / m$ . The value of magnetic field at this point is [2024]

1 $9.6 \hat{j} T$

2 $3.2 \times 10^{- 8} \hat{i} T$

3 $3.2 \times 10^{- 8} \hat{k} T$

4 $9.6 \times 10^{- 8} \hat{k} T$

Ans.
(3)

$\frac{E}{B} = 3 \times 10^{8}$

$B = \frac{E}{3 \times 10^{8}} = \frac{9.6}{3 \times 10^{8}}$

$B = 3.2 \times 10^{- 8} T \hat{B}$

$= \hat{i} \times \hat{j} = \hat{k}$

So, $\vec{B} = 3.2 \times 10^{- 8} \hat{k} T$

Solution

Q.
A plane electromagnetic wave of frequency 35 MHz travels in free space along the X-direction. At a particular point (in space and time) $\vec{E} = 9.6 \hat{j} V / m$ . The value of magnetic field at this point is [2024]

1 $9.6 \hat{j} T$

2 $3.2 \times 10^{- 8} \hat{i} T$

3 $3.2 \times 10^{- 8} \hat{k} T$

4 $9.6 \times 10^{- 8} \hat{k} T$

Ans.
(3)

$\frac{E}{B} = 3 \times 10^{8}$

$B = \frac{E}{3 \times 10^{8}} = \frac{9.6}{3 \times 10^{8}}$

$B = 3.2 \times 10^{- 8} T \hat{B}$

$= \hat{i} \times \hat{j} = \hat{k}$

So, $\vec{B} = 3.2 \times 10^{- 8} \hat{k} T$

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Solution

Q. A plane electromagnetic wave of frequency 35 MHz travels in free space along the X-direction. At a particular point (in space and time) E→=9.6j^V/m. The value of magnetic field at this point is [2024]

1 9.6j^T

2 3.2×10-8i^T

3 3.2×10-8k^T

4 9.6×10-8k^T

Ans. (3) EB=3×108 B=E3×108=9.63×108 B=3.2×10-8TB^ =i^×j^=k^ So, B→=3.2×10-8k^T

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Q.
A plane electromagnetic wave of frequency 35 MHz travels in free space along the X-direction. At a particular point (in space and time) $\vec{E} = 9.6 \hat{j} V / m$ . The value of magnetic field at this point is [2024]

1 $9.6 \hat{j} T$

2 $3.2 \times 10^{- 8} \hat{i} T$

3 $3.2 \times 10^{- 8} \hat{k} T$

4 $9.6 \times 10^{- 8} \hat{k} T$

Ans.
(3)

$\frac{E}{B} = 3 \times 10^{8}$

$B = \frac{E}{3 \times 10^{8}} = \frac{9.6}{3 \times 10^{8}}$

$B = 3.2 \times 10^{- 8} T \hat{B}$

$= \hat{i} \times \hat{j} = \hat{k}$

So, $\vec{B} = 3.2 \times 10^{- 8} \hat{k} T$