The minimum wavelength of X-rays produced by an electron accelerated through a potential difference of V volts is proportional to [2023]
1V
V2
V
(4)
Energy of X-ray = hυ=hcλ
As K.E is maximum, thus λ is minimum.
So, energy of emitted X-ray = energy of electron
hcλmin=eV⇒λmin=hce×1V⇒λmin∝1V