Q 1 :    

The minimum wavelength of X-rays produced by an electron accelerated through a potential difference of V volts is proportional to          [2023]

  • 1V

     

  • V2

     

  • V

     

  • 1V

     

(4)

Energy of X-ray = hυ=hcλ

As K.E is maximum, thus λ is minimum.

So, energy of emitted X-ray = energy of electron

hcλmin=eVλmin=hce×1Vλmin1V