Q 1 :    

de-Broglie wavelength of an electron orbiting in the n=2 state of hydrogen atom is close to (Given Bohr radius = 0.052 nm)          [2025]

  • 1.67 nm

     

  • 2.67 nm

     

  • 0.067 nm

     

  • 0.67 nm

     

(4)

2πr=nλλ=2πrn=2π×(0.052)n2Zn

   λ=2π×(0.052)×20.67nm