de-Broglie wavelength of an electron orbiting in the n=2 state of hydrogen atom is close to (Given Bohr radius = 0.052 nm) [2025]
1.67 nm
2.67 nm
0.067 nm
0.67 nm
(4)
2πr=nλ⇒λ=2πrn=2π×(0.052)n2Zn
∴ λ=2π×(0.052)×2≈0.67 nm