Q 1 :

According to Bohr's theory, the moment of momentum of an electron revolving in 4th orbit of hydrogen atom is          [2024]

  • h2π

     

  • 8hπ

     

  • 2hπ

     

  • hπ

     

(3)       

            Moment of momentum or angular momentum, L=nh2π

             put n=4

             L=4h2π=2hπ

 



Q 2 :

An electron rotates in a circle around a nucleus having positive charge Ze. Correct relation between total energy (E) of electron to its potential energy (U) is     [2024]

  • 2E = 3U

     

  • E = 2U

     

  • E = U

     

  • 2E = U

     

(4)           

            Total energy E=-kZe22r

            Potential energy U=-kZe2rU=2E

 



Q 3 :

In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of          [2024]

  • 1039

     

  • 1019

     

  • 1029

     

  • 1036

     

(1)     

            Fe=kQ1Q2r2=9×109×1.6×10-19×1.6×10-19r2

             Fg=Gm1m2r2=6.67×10-11×9.1×10-31×1.6×10-27r2

             FeFg0.23×10402.3×1039

 



Q 4 :

The angular momentum of an electron in a hydrogen atom is proportional to

(Where r is the radius of orbit of electron)                 [2024]

  • 1r

     

  • r

     

  • r

     

  • 1r

     

(3)       

           The radius of nth orbit is, rn2Z,nZr                       ...(i)

            where, Z is atomic number.

            Angular momentum is given by, L=nh2π                                 ...(ii)

            Put value of n from (i) to equation (ii),

             L=Zrh2π=(Zh2π)rLr

 



Q 5 :

A hydrogen atom in ground state is given an energy of 10.2 eV. How many spectral lines will be emitted due to transition of electrons?               [2024]

  • 6

     

  • 3

     

  • 10

     

  • 1

     

(4)        

            As, EnZ2n2

             Energy of the 2nd orbit E2=-13.64=-3.4 eV

              ΔE21=10.2 eV

              So, only possible transition is from n=2 to n=1

 



Q 6 :

The radius of third stationary orbit of electron for Bohr's atom is P. The radius of fourth stationary orbit will be          [2024]

  • 43R

     

  • 169R

     

  • 34R

     

  • 916R

     

(2)       

                rn2Z

                r4r3=4232r4=169R

 



Q 7 :

Given below are two statements:

Statement I: Most of the mass of the atom and all its positive charge are concentrated in a tiny nucleus and the electrons revolve around it, is Rutherford's model.

Statement II: An atom is a spherical cloud of positive charges with electrons embedded in it, is a special case of Rutherford's model.

In the light of the above statements, choose the most appropriate from the given below:

  • Statement I is true but Statement II is false

     

  • Both Statement I and Statement II are true

     

  • Both statement I and statement II are false

     

  • Statement I is false but Statement II is true

     

(1)           

According to Rutherford atomic model, most of mass of atom and all its positive charge is concentrated in tiny nucleus and electron revolve around it.

According to Thomson atomic model, atom is spherical cloud of positive charge with electron embedded in it.

Hence, Statement I is true but statement II is false.

 



Q 8 :

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th excited state of a hydrogen atom is:             [2024]

  • 4

     

  • 1/4

     

  • 1/2

     

  • 1

     

(3)      

           In Bohr's model, for a given state or orbit

            KE=-PE2 or |KE|=|PE|2 

            therefore, |KE||PE|=12

 



Q 9 :

An electron revolving in nth Bohr orbit has magnetic moment μn. If μn α nx, the value of x is                     [2024]

  • 2

     

  • 1

     

  • 3

     

  • 0

     

(2)         

                 Magnetic moment (m)=IA

                 =eT·πr2=e(2πrv)·πr2=erv2

                 We know that rn2 and v1n

                  So μrv

                  μn2nμn=1

 



Q 10 :

Radius of a certain orbit of hydrogen atom is 8.48 . If energy of electron in this orbit is E/x, then x

(Given a0 = 0.529 , E = energy of electron in ground state).            [2024]



(16)          We know, r=r0·n2Z=0.529n2Z

                 For hydrogen, Z=1

                 8.48=0.529n2; n2=16; n=4

                 Energy of electron in nth orbit (E)'=En2=E16x=16

 



Q 11 :

In an alpha particle scattering experiment distance of closest approach for the α particle is 4.5×10-14m. If target nucleus has atomic number 80, then maximum velocity of α-particle is ________ ×105m/s approximately.

(14πε0=9×109 SI unit, mass of α particle = 6.72×10-27 kg)          [2024]



(156)             KQqrmin=12mv2v=2K(Ze)·(2e)qmrmin=4KZe2mrmin

                     v=4×9×109×80×(1.6×10-19)26.72×10-27×4.5×10-14

                     =1.56×107m/s=156×105m/s

 



Q 12 :

If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be α7R, where α = _______ .               [2024]



(144)             Longest wavelength corresponds to transition between n=3 and n=4

                     1λ=RZ2(132-142)=RZ2(19-116)=7RZ29×16

                     λ=1447R for Z=1

                     α= 144

 



Q 13 :

A electron of hydrogen atom in an excited state is having energy En=-0.85 eV. The maximum number of allowed transitions to lower energy level is ______ .              [2024]



(6)          En=-13.6n2=-0.85n=4

               Number of transitions=n(n-1)2=4(4-1)2=6

 



Q 14 :

A hydrogen atom changes its state from n=3 to n=2. Due to recoil, the percentage change in the wavelength of emitted light is approximately 1×10-n. The value of n is ____.

[Given Rhc=13.6 eV, hc=1242 eVnm, h=6.6×10-34 mass of the hydrogen atom = 1.6×10-27 kg]             [2024]



(7)

For n=3 to n=2

ΔE=13.6(122-132)=1.9 eV

ΔE=hcλλ=hcΔE

If recoil takes place

Pi=Pf0=-mv+hλ'v=hmλ'

ΔE=12mv2+hcλ'=12m(hmλ')2+hcλ'

Now, ΔE=h22mλ'2+hcλ'

λ'2ΔE-hcλ'-h22m=0

λ'=hc±h2c2+4ΔEh22m2ΔE

λ'=hc±hc1+2ΔEmc22ΔE

λ'λ=1+(1+2ΔEmc2)122=1+1+ΔEmc22

λ'λ=1+ΔE2mc2

λ'-λλ=ΔE2mc2=1.9×1.6×10-192×1.67×10-27×9×1016=10-9

 % change10-7



Q 15 :

When a hydrogen atom going from n=2 to n=1 emits a photon, its recoil speed is x/5 m/s. Where x= ______.

(Use: mass of hydrogen atom = 1.6×10-27kg)               [2024]



(17)

The hydrogen atom transitions from n=2 to n=1,

ΔE=-10.2 eV

Recoil speed v=ΔEmc

                        =10.2 eV1.6×10-27×3×108=10.2×1.6×10-191.6×10-27×3×108

v=3.4 m/s=175 m/s

Therefore, x=17



Q 16 :

An electron projected perpendicular to a uniform magnetic field B moves in a circle. If Bohr quantization is applicable, then the radius of the electronic orbit in the first excited state is:         [2025]

  • 2hπeB

     

  • 4hπeB

     

  • h2πeB

     

  • hπeB

     

(4)

mvr=nh2π                        ...(i)

r=vmBq                              ...(ii)

n = 2

mr(rBqm)=2h2π  r=hπBq

q=e  r=hπBe



Q 17 :

The frequency of revolution of the electron in Bohr's orbit varies with n, the principal quantum number as          [2025]

  • 1n

     

  • 1n3

     

  • 1n4

     

  • 1n2

     

(2)

f=v2πr=(v0n)(12πr0n2)

f=v02πr0(1n3)=f0(1n3)



Q 18 :

Considering Bohr's atomic model for hydrogen atom:

(A) the energy of H atom in ground state is same as energy of He+ ion in its first excited state.

(B) the energy of H atom in ground state is same as that for Li++ ion in its second excited state.

(C) the energy of H atom in its ground state is same as that of He+ ion for its ground state.

(D) the energy of He+ ion in its first excited state is same as that for Li++ ion in its ground state.

Choose the correct answer from the options given below:         [2025]

  • (B), (D) only

     

  • (A), (B) only

     

  • (A), (D) only

     

  • (A), (C) only

     

(2)

E=13.6z2n2 eV

EHe+ 1st excited state = –13.6 eV

ELi2+ 2nd excited state = –13.6 eV

(A), (B) are correct.

EZn2

ZH=1  ZHe+=2  ZLi+2=3

1st excited state  n = 2

2nd excited state  n = 3

From the given statements only (A) and (B) are correct.



Q 19 :

Assuming the validity of Bohr's atomic model for hydrogen like ions the radius of Li++ ion in its ground state is given by 1Xa0, where X =. (Where a0 is the first Bohr's radius.)          [2025]

  • 2

     

  • 1

     

  • 3

     

  • 9

     

(3)

r=a0n2Z and Z=3 for Li+2 and n=1

  r=a0123=a03

  X=3



Q 20 :

Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : The Bohr model is applicable to hydrogen and hydrogen-like atoms only.

Reason (R) : The formulation of Bohr model does not include repulsive force between electrons.

In the light of the above statements, choose the correct answer from the options given below:          [2025]

  • Both (A) and (R) are true but (R) is NOT the correct explanation of (A).

     

  • (A) is false but R is true.

     

  • Both (A) and (R) are true and (R) is the correct explanation of (A).

     

  • (A) is true but (R) is false.

     

(3)

Assertion is correct, Reason is correct as there are no two electrons for repulsion.

Therefore (3) is most appropriate response



Q 21 :

Consider the Bohr model of hydrogen like atoms, the ratio of the radius of 5th orbit of the electron in Li2+ and He+ is          [2025]

  • 32

     

  • 49

     

  • 94

     

  • 23

     

(4)

r=a0·n2Z

For Li2+r5=a0·253

for He+r5=a0·252

  rLi2+rHe+=23



Q 22 :

Given below are two statements:

Statement (I) : The dimensions of Planck's constant and angular momentum are same.

Statement (II) : In Bohr's model electron revolve around the nucleus only in those orbits for which angular momentum is integral multiple of Planck's constant.

In the light of the above statements, choose the most appropriate answer from the options given below:          [2025]

  • Both Statement I and Statement II are correct.

     

  • Statement I is incorrect but Statement II is correct.

     

  • Statement I is correct but Statement II is incorrect.

     

  • Both Statement I and Statement II are incorrect.

     

(3)

E = hf

ML2T2=[h]×[T1]

[h]=[ML2T1]

L=[MVR]=[ML2T1]

L=nh2π

L is integral multiple of h2π



Q 23 :

In a hydrogen like ion, the energy difference between the 2nd excitation energy state and ground is 108.8 eV. The atomic number of the ion is         [2025]

  • 4

     

  • 2

     

  • 1

     

  • 3

     

(4)

E=13.6Z2[1n121n22]

13.6Z2[1119]=108.8

13.6×89(Z2)=108.8  Z=3



Q 24 :

An electron in the hydrogen atom initially in the fourth excited state makes a transition to n energy state by emitting a photon of energy 2.86 eV. The integer value of n will be ________.          [2025]



(2)

E=13.6(1n121n12)

2.86=13.6(1n2152)

1n2=0.21+125

n2=4  n=2



Q 25 :

A photon is emitted in transition from n=4 to n=1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h=4×10-15 eV s)       [2023]

  • 941 nm

     

  • 974 nm

     

  • 99.3 nm

     

  • 94.1 nm

     

(4)

hcλ=+13.6 eV[11-142]

4×10-15×3×10-8λ=13.6[1516]

So, λ=94.1 nm



Q 26 :

Speed of an electron in Bohr's 7th orbit for Hydrogen atom is 3.6×106 m/s. The corresponding speed of the electron in 3rd orbit, in m/s is             [2023]

  • 1.8×106

     

  • 7.5×106

     

  • 3.6×106

     

  • 8.4×106

     

(4)

VnZn

z=1

 Vn1n

 V3V7=73

 V3=73V7=73×3.6×106 m/s=8.4×106 m/s



Q 27 :

The radius of electron’s second stationary orbit in Bohr’s atom is R. The radius of 3rd orbit will be          [2023]

  • R3

     

  • 2.25 R

     

  • 3 R

     

  • 9 R

     

(2)

rn2Z

r2ndr3rd=(n2n3)2

Rr3rd=(23)2

r3rd=94R=2.25R



Q 28 :

A small particle of mass m moves in such a way that its potential energy U=12mω2r2 where ω is constant and r is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of nth orbit will be proportional to.               [2023]

  • n

     

  • n

     

  • n2

     

  • 1n

     

(1)

U=12mω2r2

F=-dUdr=-mω2r

Now  mω2r=mv2r  v=ωr    (i)

and  mvr=nh2π    (ii)

From (i) and (ii),

mωr2=nh2π  rn



Q 29 :

A light of energy 12.75 eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited states. The angular momentum of the atom in the excited state is xπ×10-17 eV s. The value of x is _________

(use  h=4.14×10-15 eVs, c=3×108 ms-1)                  [2023]



(828)

In the ground state energy=-13.6 eV

So energy  -13.6 eVn2=-13.6+12.75

           -13.6 eVn2=-0.85

           n=16=4

Angular momentum=nh2π=4h2π=2hπ

Angular momentum=2π×4.14×10-15=828×10-17πeVs



Q 30 :

Experimentally it is found that 12.8 eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the electron in a hydrogen atom is 9x×10-10 m. The value of the x is _________.

(1 eV=1.6×10-19 J, 14πε0=9×109 Nm2/C2 and electronic charge =1.6×10-19 J C)               [2023]



(16)

Binding energy of system=ke22r joule  and ke22r=12.8 eV

          9×109×(1.6×10-19)22r=12.8×1.6×10-19

  r=9×109×1.6×10-1912.8×2

  r=9×10-1016