Radius of a certain orbit of hydrogen atom is 8.48 . If energy of electron in this orbit is , then x

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
Radius of a certain orbit of hydrogen atom is 8.48 $Å$ . If energy of electron in this orbit is $E / x$ , then $x$ =

(Given $a_{0}$ = 0.529 $Å$ , E = energy of electron in ground state). [2024]

Ans.
(16) $We know, r = r_{0} \cdot \frac{n^{2}}{Z} = 0.529 \frac{n^{2}}{Z}$

$For hydrogen, Z = 1$

$8.48 = 0.529 n^{2}; n^{2} = 16; n = 4$

$Energy of electron in n^{t h} orbit {(E)}^{'} = \frac{E}{n^{2}} = \frac{E}{16} \Rightarrow x = 16$

Want Us to Email you About Special Offers & Updates?