The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the Sth excited state of a hydrogen atom is:

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Solution

Q.
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th excited state of a hydrogen atom is: [2024]

1 4

2 1/4

3 1/2

4 1

Ans.
(3)

In Bohr's model, for a given state or orbit

$K E = - \frac{P E}{2}$ or $| K E | = \frac{| P E |}{2}$

therefore, $\frac{| K E |}{| P E |} = \frac{1}{2}$

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