Q 11 :    

In an alpha particle scattering experiment distance of closest approach for the α particle is 4.5×10-14m. If target nucleus has atomic number 80, then maximum velocity of α-particle is ________ ×105m/s approximately.

(14πε0=9×109 SI unit, mass of α particle = 6.72×10-27 kg)          [2024]



(156)             KQqrmin=12mv2v=2K(Ze)·(2e)qmrmin=4KZe2mrmin

                     v=4×9×109×80×(1.6×10-19)26.72×10-27×4.5×10-14

                     =1.56×107m/s=156×105m/s

 



Q 12 :    

If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be α7R, where α = _______ .               [2024]



(144)             Longest wavelength corresponds to transition between n=3 and n=4

                     1λ=RZ2(132-142)=RZ2(19-116)=7RZ29×16

                     λ=1447R for Z=1

                     α= 144

 



Q 13 :    

A electron of hydrogen atom in an excited state is having energy En=-0.85 eV. The maximum number of allowed transitions to lower energy level is ______ .              [2024]



(6)          En=-13.6n2=-0.85n=4

               Number of transitions=n(n-1)2=4(4-1)2=6

 



Q 14 :    

A hydrogen atom changes its state from n=3 to n=2. Due to recoil, the percentage change in the wavelength of emitted light is approximately 1×10-n. The value of n is ____.

[Given Rhc=13.6 eV, hc=1242 eVnm, h=6.6×10-34 mass of the hydrogen atom = 1.6×10-27 kg]             [2024]



(7)

For n=3 to n=2

ΔE=13.6(122-132)=1.9 eV

ΔE=hcλλ=hcΔE

If recoil takes place

Pi=Pf0=-mv+hλ'v=hmλ'

ΔE=12mv2+hcλ'=12m(hmλ')2+hcλ'

Now, ΔE=h22mλ'2+hcλ'

λ'2ΔE-hcλ'-h22m=0

λ'=hc±h2c2+4ΔEh22m2ΔE

λ'=hc±hc1+2ΔEmc22ΔE

λ'λ=1+(1+2ΔEmc2)122=1+1+ΔEmc22

λ'λ=1+ΔE2mc2

λ'-λλ=ΔE2mc2=1.9×1.6×10-192×1.67×10-27×9×1016=10-9

 % change10-7



Q 15 :    

When a hydrogen atom going from n=2 to n=1 emits a photon, its recoil speed is x/5 m/s. Where x= ______.

(Use: mass of hydrogen atom = 1.6×10-27kg)               [2024]



(17)

The hydrogen atom transitions from n=2 to n=1,

ΔE=-10.2 eV

Recoil speed v=ΔEmc

                        =10.2 eV1.6×10-27×3×108=10.2×1.6×10-191.6×10-27×3×108

v=3.4 m/s=175 m/s

Therefore, x=17