If a substance ‘A’ dissolves in solution of a mixture of ‘B’ and ‘C’ with their respective number of moles as and . Mole fraction of C in the solution is

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Q.
If a substance ‘A’ dissolves in solution of a mixture of ‘B’ and ‘C’ with their respective number of moles as $n_{A}, n_{B}$ and $n_{C}$ . Mole fraction of C in the solution is [2024]

Solution

Q.
If a substance ‘A’ dissolves in solution of a mixture of ‘B’ and ‘C’ with their respective number of moles as $n_{A}, n_{B}$ and $n_{C}$ . Mole fraction of C in the solution is [2024]

1 $\frac{n_{C}}{n_{A} \times n_{B} \times n_{C}}$

2 $\frac{n_{C}}{n_{A} + n_{B} + n_{C}}$

3 $\frac{n_{C}}{n_{A} - n_{B} - n_{C}}$

4 $\frac{n_{B}}{n_{A} + n_{B}}$

Ans.
(2)

Mole fraction of any substance = $\frac{Moles of that substance}{Total number of moles}$

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Solution

Q. If a substance ‘A’ dissolves in solution of a mixture of ‘B’ and ‘C’ with their respective number of moles as nA,nB and nC. Mole fraction of C in the solution is [2024]

1 nCnA×nB×nC

2 nCnA+nB+nC

3 nCnA-nB-nC

4 nBnA+nB

Ans. (2) Mole fraction of any substance = Moles of that substanceTotal number of moles

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Q.
If a substance ‘A’ dissolves in solution of a mixture of ‘B’ and ‘C’ with their respective number of moles as $n_{A}, n_{B}$ and $n_{C}$ . Mole fraction of C in the solution is [2024]

1 $\frac{n_{C}}{n_{A} \times n_{B} \times n_{C}}$

2 $\frac{n_{C}}{n_{A} + n_{B} + n_{C}}$

3 $\frac{n_{C}}{n_{A} - n_{B} - n_{C}}$

4 $\frac{n_{B}}{n_{A} + n_{B}}$

Ans.
(2)

Mole fraction of any substance = $\frac{Moles of that substance}{Total number of moles}$