A solution of ? is 31.4% ? by mass and has a density of 1.25 g/mL. The molarity of the ? solution is _____ M (nearest integer)

Question

A solution of $H_{2} {SO}_{4}$ is 31.4% $H_{2} {SO}_{4}$ by mass and has a density of 1.25 g/mL. The molarity of the $H_{2} {SO}_{4}$ solution is _____ M (nearest integer)

[Given molar mass of $H_{2} {SO}_{4}$ = 98 g ${mol}^{- 1}$ ] [2024]

Smart Achievers · Accepted Answer

(4)

$31.4 % H_{2} {SO}_{4} by mass means:$

$31.4 {gm H}_{2} {SO}_{4} in 100gm solution$

$\Rightarrow \frac{31.4}{98} mol = 0.32 {mol H}_{2} {SO}_{4} in \frac{100 g}{1.25 {g mL}^{- 1}}$

$= 80 mL solution$

$Molarity = \frac{n_{solute}}{V_{solution} (in mL)} \times 1000 = \frac{0.32}{80} \times 1000 M = 4 M$

Solution

Q.
A solution of $H_{2} {SO}_{4}$ is 31.4% $H_{2} {SO}_{4}$ by mass and has a density of 1.25 g/mL. The molarity of the $H_{2} {SO}_{4}$ solution is _____ M (nearest integer)

[Given molar mass of $H_{2} {SO}_{4}$ = 98 g ${mol}^{- 1}$ ] [2024]

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Solution

Q. A solution of H2SO4 is 31.4% H2SO4 by mass and has a density of 1.25 g/mL. The molarity of the H2SO4 solution is _____ M (nearest integer) [Given molar mass of H2SO4 = 98 g mol-1] [2024]

Ans. (4) 31.4% H2SO4 by mass means: 31.4 gm H2SO4 in 100gm solution ⇒31.498 mol=0.32 mol H2SO4 in 100 g1.25 g mL-1 =80 mL solution Molarity=nsoluteVsolution (in mL)×1000=0.3280×1000 M=4 M

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Q.
A solution of $H_{2} {SO}_{4}$ is 31.4% $H_{2} {SO}_{4}$ by mass and has a density of 1.25 g/mL. The molarity of the $H_{2} {SO}_{4}$ solution is _____ M (nearest integer)

[Given molar mass of $H_{2} {SO}_{4}$ = 98 g ${mol}^{- 1}$ ] [2024]