The density of ‘x’ M solution (‘x’ molar) of NaOH is 1.12 g , while in molality, the concentration of the solution is 3 m (3 molal). Then x is (Given: Molar mass of NaOH is 40 g/mol)

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Solution

Q.
The density of ‘x’ M solution (‘x’ molar) of NaOH is 1.12 g ${mL}^{- 1}$ , while in molality, the concentration of the solution is 3 m (3 molal). Then x is (Given: Molar mass of NaOH is 40 g/mol) [2024]

1 3.8

2 3.5

3 2.8

4 3.0

Ans.
(4)

$molality = \frac{1000 \times Molarity}{1000 \times density - Molarity \times M_{solute}}$

$3 = \frac{1000 x}{1000 \times 1.12 - x \times 40}$

$3360 - 120 x = 1000 x$

$1120 x = 3360$

$x = 3$

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