A body of mass 2 kg moving with velocity of enters in to a constant force field of 6 N directed along positive z-axis. If the body remains in the filed for a period of seconds, then velocity of the body when it emerges from force field is [2025]

Question

A body of mass 2 kg moving with velocity of ${\vec{v}}_{i n} = 3 \hat{i} + 4 \hat{j} {ms}^{- 1}$ enters in to a constant force field of 6 N directed along positive z-axis. If the body remains in the field for a period of $\frac{5}{3}$ seconds, then velocity of the body when it emerges from force field is [2025]

Smart Achievers · Accepted Answer

(2)

$\vec{a} = \frac{6}{2} (\hat{k}) {ms}^{- 2} = 3 (\hat{k}) {ms}^{- 2}, t = \frac{5}{3} s$

$\vec{u} = (3 \hat{i} + 4 \hat{j}) {ms}^{- 1}$

$\vec{v} = \vec{u} + \vec{a t} = (3 \hat{i} + 4 \hat{j} + 5 \hat{k}) {ms}^{- 1}$

Solution

1 $4 \hat{i} + 3 \hat{j} + 5 \hat{k}$

2 $3 \hat{i} + 4 \hat{j} + 5 \hat{k}$

3 $3 \hat{i} + 4 \hat{j} - 5 \hat{k}$

4 $3 \hat{i} + 4 \hat{j} + \sqrt{5} \hat{k}$

Ans.
(2)

$\vec{a} = \frac{6}{2} (\hat{k}) {ms}^{- 2} = 3 (\hat{k}) {ms}^{- 2}, t = \frac{5}{3} s$

$\vec{u} = (3 \hat{i} + 4 \hat{j}) {ms}^{- 1}$

$\vec{v} = \vec{u} + \vec{a t} = (3 \hat{i} + 4 \hat{j} + 5 \hat{k}) {ms}^{- 1}$

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Solution

Q. A body of mass 2 kg moving with velocity of v→in=3i^+4j^ ms–1 enters in to a constant force field of 6 N directed along positive z-axis. If the body remains in the field for a period of 53 seconds, then velocity of the body when it emerges from force field is [2025]

1 4i^+3j^+5k^

2 3i^+4j^+5k^

3 3i^+4j^–5k^

4 3i^+4j^+5k^