Q.

At any instant the velocity of a particle of mass 500 g is (2ti^+3t2j^)m s-1. If the force acting on the particle at t= 1 s is (i^+xj^) N, then the value of x will be        [2023]

1 3  
2 6  
3 2  
4 4  

Ans.

(1)

v→=2ti^+3t2j^

a→=2i^+6tj^

At t=1, a→=2i^+6j^

F→=ma→=0.5(2i^+6j^)=i^+3 j^

F→=i^+xj^

Hence x = 3