At any instant the velocity of a particle of mass 500 g is (2ti^+3t2j^)m s-1. If the force acting on the particle at t= 1 s is (i^+xj^) N, then the value of x will be [2023]
(1)
v→=2ti^+3t2j^
a→=2i^+6tj^
At t=1, a→=2i^+6j^
F→=ma→=0.5(2i^+6j^)=i^+3 j^
F→=i^+xj^
Hence x = 3