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Solution


Q.

Force acts for 20 s on a body of mass 20 kg, starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be     [2023]
1 40 N  
2 5 N  
3 20 N  
4 10 N  

Ans.

(2)

50=V×10 ⇒ V=5 m/s

V=0+a×20

⇒ 5=a×20 ⇒ a=14m/s2

F=ma=20×14=5 N