The position vector of a particle related to time ttt is given by The direction of net force experienced by the particle is [2023]

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Solution

Q.
The position vector of a particle related to time $t$ is given by $\hat{r} = (10 t \hat{i} + 15 t^{2} \hat{j} + 7 \hat{k}) m$

The direction of net force experienced by the particle is [2023]

1 Positive y-axis

2 Positive $x$ -axis

3 Positive z-axis

4 In $x - y$ plane

Ans.
(1)

$\hat{r} = 10 t \hat{i} + 15 t \hat{j} + 7 \hat{k}$

$\vec{v} = 10 \hat{i} + 30 t \hat{j}$

$\vec{a} = 30 \hat{j}$

$So, net force is along the + y direction.$

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