The kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying brakes, car A stops after 1000 m and car B stops after 1500 m. If and are the forces applied by the brakes on cars A and B, respectively, then the ratio is [2025]
(4)
According to work - energy theorem,
Work done = change in kinetic energy
For car A,
...(i)
Similarly for car B, ...(ii)
From eqn. (i) and (ii)
An object moving along horizontal -direction with kinetic energy 10 J is displaced through , by the force . The kinetic energy of the object at the end of the displacement is: [2024]
10 J
16 J
4 J
6 J
(3)
Given, or
Initial Kinetic energy,
Using work-energy theorem,
Consider a drop of rain water having mass 1 g falling from a height of 1 km. It hits the ground with a speed of 50 . Take constant with a value 10 . The work done by the (i) gravitational force and the (ii) resistive force of air is [2017]
(i) 1.25 J (ii) - 8.25 J
(i) 100 J (ii) 8.75 J
(i) 10J (ii) - 8.75 J
(i) - 10J (ii) - 8.25 J
(3)
Here,
(i) The work done by the gravitational force
(ii) The total work done by gravitational force and the resistive force of air is equal to change in kinetic energy of rain drop.
or
A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to by the end of the second revolution after the beginning of the motion? [2016]
(3)
Here,
Using work energy theorem,
Work done by all the forces = Change in KE