Q 1 :

Consider a rectangular sheet of solid material of length l = 9 cm and width d = 4 cm. The coefficient of linear expansion is α=3.1×10–5 K–1 at room temperature and one atmospheric pressure. The mass of sheet m = 0.1 kg and the specific heat capacity Cv=900 J kg–1 K–1. If the amount of heat supplied to the material is 8.1×102 J then change in area of the rectangular sheet is:          [2025]

  • 2.0×10–6 m2

     

  • 3.0×10–7 m2

     

  • 6.0×10–7 m2

     

  • 4.0×10–7 m2

     

(1)

Q=mc△T

8.1×102=900×0.1×△T ⇒ △T=9K

△A=A·2α△T

             =36×2×3.1×10–5×9×10–4=2×10–6 m2

 



Q 2 :

A hole is drilled in a metal sheet. At 27°C, the diameter of the hole is 5 cm. When the sheet is heated to 177°C, the change in the diameter of the hole is d×10-3 cm. The value of d will be _______ if the coefficient of linear expansion of the metal is 1.6×10-5/°C.                      [2023]



(12)

d0 at 27°C and d1 at 177°C

d1=d0(1+αΔT)

(d1-d0)=5×1.6×10-5×150 cm=12×10-3 cm



Q 3 :

A thin rod having a length of 1 m and area of cross-section 3×10-6 m2 is suspended vertically from one end. The rod is cooled from 210°C to 160°C. After cooling, a mass M is attached at the lower end of the rod such that the length of the rod again becomes 1 m. Young's modulus and coefficient of linear expansion of the rod are 2×1011 Nm-2 and 2×10-5 K-1, respectively. The value of M is ______ kg.  (Take g=10 ms-2)                   [2023]



(60)

If Δl is decrease in length of rod due to decrease in temperature

Δl=lαΔT

α=2×10-5 K-1

ΔT=(210-160)=50 K

Δl=1×2×10-5×50=10-3 m

Young's Modulus =Y=F/AΔl/l,  A=3×10-6 m2

2×1011=Mg/3×10-610-3/1

Mg=2×1011×3×10-9=6×10-2

⇒ M=60 kg



Q 4 :

An aluminium and steel rods having same lengths and cross-sections are joined to make total length of 120 cm at 30°C. The coefficient of linear expansion of aluminium and steel are 24×10-6/°C and 1.2×10-5/°C respectively. The length of this composite rod when its temperature is raised to 100°C, is ________ cm.   [2026]

  • 120.20

     

  • 120.06

     

  • 120.03

     

  • 120.15

     

(4)

ℓfinal=ℓ0(1+αAΔT)+ℓ0(1+αBΔT)

         =ℓ0[2+(αA+αB)ΔT]

         =60[2+(36×10-6)×70]

         =60[2+0.0025]

          =120.15 cm



Q 5 :

A brass wire of length 2 m and radius 1 mm at 27°C is held taut between two rigid supports. Initially, it was cooled to a temperature of -43°C creating a tension T in the wire. The temperature to which the wire has to be cooled in order to increase the tension in it to 1.4T, is _________ C∘.               [2026]

  • - 80

     

  •  - 65

     

  • - 71

     

  • - 86

     

(3)

T=αYA(27-(-43))          ...(i)

1.4 T=αYA(27-θ)             ...(ii)

Using (ii)/(i):

1.4=27-θ70

27-θ=98  ∴  θ=-71°C



Q 6 :

Which of the following best represents the temperature versus heat supplied graph for water, in the range of -20°C to 120°C?  [2026]

  •  

  •  

  •  

  •  

(2)

-20°C to 0°C: q=msiceΔT At 0°C, phase change takes place.

0°C to 100°C: q=mswaterΔT At 100°C, phase change takes place.



Q 7 :

Two large holes are cut in a metal sheet as shown. If this is heated, which distance will decrease:

  • BC

     

  • AB

     

  • AC

     

  • None of these

     

(4)

Distance between any two points when only increase.



Q 8 :

The temperature of a metal strip having coefficient of linear expansion α is increased from T1 to T2 resulting in increase of its length by ΔL1. The temperature is further increased from T2 to T3 such that the increase in its length is ΔL2.

Given T3+T1=2T2 and T2-T1=ΔT, the value of ΔL2 is ______.             [2026]

  • ΔL1[1+2α2(ΔT)2]

     

  • ΔL1[1+α2(ΔT)2]

     

  • ΔL1[1+2αΔT]

     

  • ΔL1[1+αΔT]

     

(4)

ΔL1=αL1ΔT

ΔL2=(L1+ΔL1)(T3-T2)

ΔL2=(L1+ΔL1)ΔT

ΔL2=(ΔL1αΔT+ΔL1)αΔT

ΔL2=ΔL1[1+αΔT]