Q 31 :

The vapour pressure vs. temperature curve for a solution–solvent system is shown below:

The boiling point of the solvent is ______ °C.         [2023]



(82)

The temperature at which vapour pressure of solvent becomes 1 atm is called normal B.P. of solvent. So, the boiling point of the solvent is 82°C.



Q 32 :

If the boiling points of two solvents X and Y (having same molecular weights) are in the ratio 2 : 1 and their enthalpy of vaporization are in the ratio 1 : 2, then the boiling point elevation constant of X is m times the boiling point elevation constant of Y. The value of m is ________ (Nearest Integer)            [2023]



(8)

ΔTb=Kbm

Kb=RTb2×Msolvent1000×ΔHvap

(ΔTb)X(ΔTb)Y=[(Tb)X(Tb)Y]2×MXMY×ΔHYΔHX=(21)2(11)×21=8



Q 33 :

An aqueous solution of volume 300 cm3 contains 0.63 g of protein. The osmotic pressure of the solution at 300 K is 1.29 mbar. The molar mass of the protein is ________ g mol-1. Given: R = 0.083 L bar K-1 mol-1                              [2023]



(40535)

π=W/MVRT

or  M=W×R×Tπ×V=0.63×0.083×3001.29×10-3×300×10-3

or M=40535 g/mol



Q 34 :

Solutions of 12 g of non-electrolyte (A) prepared by dissolving it in 1000 mL of water exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The empirical formula of A is CH2O. The molecular mass of A is ______ g. (Nearest integer)               [2023]



(240)

For isotonic solutions

π1=π2

C1=C2 (For non-electrolyte)

(12MA×1)=0.05

MA=240



Q 35 :

A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute A of molar mass 60 g mol-1 and 0.9 g of a non-volatile non-electrolyte solute B of molar mass 180 g mol-1 in 100 mL H2O at 27°C. Osmotic pressure of the solution will be:

[Given: R = 0.082 L atm K-1 mol-1]                     [2026]

  • 1.23 atm

     

  • 1.47 atm

     

  • 2.46 atm

     

  • 0.82 atm

     

(3)

 



Q 36 :

Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and PQ2.When 1 g of PQ is dissolved in 50 g of solvent ‘A’, ΔTb was 1.176 K while when 1 g of PQ2 is dissolved in 50 g of solvent 'A', ΔTb was 0.689 K. (Kb of ‘A’=5 K kg mol-1). The molar masses of elements P and Q (in g mol⁻¹) respectively, are:   [2026]

  • 65, 145

     

  • 70, 110

     

  • 60, 25

     

  • 25, 60

     

(4)

(ΔTb)PQ=Kbm

1.176=5×1M1×100050

M1=85.03

(ΔTb)PQ2=5×1M2×100050=0.689

M2=145.13

Let molar mass of P & Q are MP and MQ respectively

MP+MQ=85.03

MP+2MQ=145.13

MP=24.9325

MQ=60.160



Q 37 :

Consider the following aqueous solutions.    [2026]

I. 2.2 g Glucose in 125 mL of solution.
II. 1.9 g Calcium chloride in 250 mL of solution.
III. 9.0 g Urea in 500 mL of solution.
IV. 20.5 g Aluminium sulphate in 750 mL of solution.

The correct increasing order of boiling point of these solutions will be:
[Given : Molar mass in g mol¹ : H = 1, C = 12, N = 14, O = 16, Cl = 35.5, Ca = 40, Al = 27 and S = 32]

  • III < I < II < IV

     

  • I < II < III < IV

     

  • II < III < I < IV

     

  • II < III < IV < I

     

(2)

 



Q 38 :

Consider the above electrochemical cell where a metal electrode (M) is undergoing redox reaction by forming M+, (MM++e-). The cation M+ is present in two different concentrations c1 and c2 as shown above. Which of the following statement is correct for generating a positive  cell potential?  [2026]

  • If c1 is present at cathode, then c1<c2

     

  • If c1 is present at anode, then c1>c2

     

  • If c1 is present at anode, then c1=c2

     

  • If c1 is present at cathode, then c1>c2.

     

(4)

 



Q 39 :

A substance ‘X’ (1.5 g) dissolved in 150 g of a solvent ‘Y’ (molar mass = 300 g mol¹) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent ‘Y’ is ______ × 10². (nearest integer)

[Given : Kb of the solvent = 5.0 K kg mol¹]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.         [2026]



3

 



Q 40 :

The osmotic pressure of a living cell is 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is ______ g L¹. (Nearest integer)

Given : R = 0.08 L atm K¹ mol¹

Assume complete dissociation of NaCl

(Given : Molar mass of Na and Cl are 23 and 35.5 g mol¹ respectively.)           [2026]



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