Q 31 :

The vapour pressure vs. temperature curve for a solution–solvent system is shown below:

[IMAGE 140]

The boiling point of the solvent is ______ °C.         [2023]



(82)

The temperature at which vapour pressure of solvent becomes 1 atm is called normal B.P. of solvent. So, the boiling point of the solvent is 82°C.



Q 32 :

If the boiling points of two solvents X and Y (having same molecular weights) are in the ratio 2 : 1 and their enthalpy of vaporization are in the ratio 1 : 2, then the boiling point elevation constant of X is m times the boiling point elevation constant of Y. The value of m is ________ (Nearest Integer)            [2023]



(8)

ΔTb=Kbm

Kb=RTb2×Msolvent1000×ΔHvap

(ΔTb)X(ΔTb)Y=[(Tb)X(Tb)Y]2×MXMY×ΔHYΔHX=(21)2(11)×21=8



Q 33 :

An aqueous solution of volume 300 cm3 contains 0.63 g of protein. The osmotic pressure of the solution at 300 K is 1.29 mbar. The molar mass of the protein is ________ g mol-1. Given: R = 0.083 L bar K-1 mol-1                              [2023]



(40535)

π=W/MVRT

or  M=W×R×Tπ×V=0.63×0.083×3001.29×10-3×300×10-3

or M=40535 g/mol



Q 34 :

Solutions of 12 g of non-electrolyte (A) prepared by dissolving it in 1000 mL of water exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The empirical formula of A is CH2O. The molecular mass of A is ______ g. (Nearest integer)               [2023]



(240)

For isotonic solutions

π1=π2

C1=C2 (For non-electrolyte)

(12MA×1)=0.05

MA=240