Q.

An aqueous solution of volume 300 cm3 contains 0.63 g of protein. The osmotic pressure of the solution at 300 K is 1.29 mbar. The molar mass of the protein is ________ g mol-1. Given: R = 0.083 L bar K-1 mol-1                              [2023]


Ans.

(40535)

π=W/MVRT

or  M=W×R×Tπ×V=0.63×0.083×3001.29×10-3×300×10-3

or M=40535 g/mol