If the boiling points of two solvents X and Y (having same molecular weights) are in the ratio 2 : 1 and their enthalpy of vaporization are in the ratio 1 : 2, then the boiling point elevation constant of X is m times the boiling point elevation constant

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Solution

Q.
If the boiling points of two solvents X and Y (having same molecular weights) are in the ratio 2 : 1 and their enthalpy of vaporization are in the ratio 1 : 2, then the boiling point elevation constant of X is m times the boiling point elevation constant of Y. The value of m is ________ (Nearest Integer) [2023]

Ans.
(8)

$Δ T_{b} = K_{b} m$

$K_{b} = \frac{R T_{b}^{2} \times M_{solvent}}{1000 \times Δ H_{vap}}$

$\frac{{(Δ T_{b})}_{_{X}}}{{(Δ T_{b})}_{Y}} = {[\frac{{(T_{b})}_{X}}{{(T_{b})}_{Y}}]}^{2} \times \frac{M_{X}}{M_{Y}} \times \frac{Δ H_{Y}}{Δ H_{X}} = {(\frac{2}{1})}^{2} (\frac{1}{1}) \times \frac{2}{1} = 8$

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